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Chapter 17Rates, organic chemistry and analysisAQA Trilogy · Edexcel · OCR GatewayFoundation + HigherDouble awardNot yet teacher-reviewed

GCSE Combined Science Rates & equilibrium revision

Reactions are collision sports: more crashes with more energy means more product per second. Measure rates with syringes, balances and vanishing crosses, read curves and tangents like a stock chart, meet the catalyst that never gets used up, and let dynamic equilibrium call the shots at Higher tier.

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Not yet teacher-reviewed. Written by the QuizQuip team against the DfE GCSE combined science subject content; a teacher has not checked it yet. Spotted a mistake? Tell us

Overview

What you’ll learn

  • Calculate mean rates with the right units and read rates at instants from tangents.
  • Explain every rate factor through collision theory without drifting into myths.
  • Describe catalysts correctly — lower activation energy, unchanged mass, same yield.
  • Run and evaluate the concentration required practical, comparing results with 1/time.
  • Describe reversible reactions and dynamic equilibrium in closed systems.
  • Predict equilibrium shifts when concentration or pressure changes (Higher).

Specification checklist (AQA Trilogy 8464 · Edexcel 1SC0 · OCR Gateway J250)

Statements are paraphrased from the shared DfE combined science subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. This chapter covers only what Combined Science (double award) examines — separate-science extras live on the GCSE Biology, Chemistry and Physics hubs. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.

Foundation — every student

  • 17.1Calculate the mean rate of a reaction from the quantity of product formed or reactant used divided by the time taken, with units such as cm³/s, g/s or mol/s.
  • 17.2Describe the factors that change the rate — concentration or pressure, temperature, surface area of solids and catalysts — and explain each using collision theory: reactions need collisions with at least the activation energy, and factors raise collision frequency or energy.
  • 17.3Describe catalysts as substances that increase the rate by providing a lower-activation-energy route while remaining chemically unchanged and unchanged in mass at the end.
  • 17.4Interpret rate graphs: the steepest section is the fastest rate, the curve flattens when a reactant is used up, and the rate at a chosen moment is found from the gradient of a tangent to the curve.
  • 17.5Describe the required practical of investigating how concentration changes the rate — by the disappearing-cross (precipitate) method or by collecting gas — including the variables that must be controlled, the method, and the use of 1/time comparisons.
  • 17.6Describe reversible reactions (such as hydrated and anhydrous copper(II) sulfate) and dynamic equilibrium: in a closed system the forward and reverse reactions run at equal rates, so the amounts of reactants and products stay constant.

Higher — Higher tier only

  • 17.7(Higher) Predict, using the principle that an equilibrium shifts to oppose a change, the effect of changing concentration or pressure on the position of equilibrium (for example, increasing pressure favours the side with fewer gas molecules).

Key points

  1. 1Mean rate = quantity changed ÷ time taken — cm³/s for gas, g/s for mass loss, mol/s for moles.
  2. 2Collision theory: particles must collide with at least the activation energy; anything that makes collisions more frequent or more energetic raises the rate.
  3. 3Rate rises with temperature (faster, more energetic collisions), concentration/pressure (more particles per volume), and surface area (more exposed solid).
  4. 4Catalysts lower the activation energy by offering an alternative route — and emerge chemically unchanged, with exactly the same mass.
  5. 5Rate graphs: steepest at the start, flattening as a reactant runs out; the rate at an instant is the gradient of a tangent.
  6. 6Reversible reactions reach dynamic equilibrium in a closed system: forward and reverse run at equal rates, amounts constant.
  7. 7(Higher) Equilibrium shifts to oppose a change — more pressure pushes it to the side with fewer gas molecules.

Notes · 1 of 4

Rates, collision theory and the four factors

Every “explain the rate” answer is a collision story.

The mean rate of a reaction is how much stuff changes divided by how long it takes: rate = quantity changed ÷ time. A reaction filling a syringe with 72 cm³ of gas in 45 s runs at 72 ÷ 45 = 1.6 cm³/s. Rates carry units — cm³/s for gas volume, g/s for mass lost, mol/s for moles — and forgetting the unit drops the mark.

Collision theory explains every factor in one breath: particles react only when they collide with at least the activation energy. Temperature up → particles move faster → collisions more frequent *and* more energetic, so many more succeed. Concentration or pressure up → more particles in the same volume → more collisions per second. Surface area up → a powder exposes far more particles than one lump → more collisions at the surface. A catalyst plays a different game: it offers a route with a lower activation energy, so the same collisions succeed more often — and it emerges unchanged, with exactly the mass it went in with.

The four factors, one explanation each
FactorWhat it changesCollision story
Temperature ↑Speed and energy of particlesCollide more often and more exceed Ea
Concentration/pressure ↑Particles per volumeCollide more often
Surface area ↑Exposed solid particlesMore collision sites
CatalystRoute takenLower activation energy

Worked example — the explanation template

Q: Why does powdered chalk fizz faster than a lump in the same acid? A: The powder has a larger surface area, so more particles are exposed for collisions → more successful collisions per second → faster rate. Name the factor, quote the collision change, conclude the rate. Three lines, full marks.

Notes · 2 of 4

Measuring rates: methods and graphs

Syringes, balances and vanishing crosses — then read the curve.

Pick the method from the reaction. Gas made? Collect it in a gas syringe (or over water). Gas escaping from an open flask? Follow the mass loss on a balance. A precipitate clouding a solution? Time a disappearing cross under the beaker. All three plot quantity against time — and all three curves tell the same story: steepest at the start (reactants plentiful), flattening as a reactant runs out, perfectly flat when the reaction is over.

The mean rate covers a whole interval; the rate at one moment needs a tangent. Draw the line that just kisses the curve at your chosen time, form a large triangle, and divide rise by fall. A tangent at 15 s that climbs 33 cm³ over the next 15 s gives a rate of 33 ÷ 15 = 2.2 cm³/s at that instant. Once the curve is flat, the gradient — and the rate — is zero.

Worked example — tangent vs mean

A curve passes through 20 cm³ at 10 s and 56 cm³ at 30 s. The mean rate between those times is (56 − 20) ÷ (30 − 10) = 36 ÷ 20 = 1.8 cm³/s. That is an average for the interval — the instantaneous rate at 20 s could differ, because the curve’s steepness fades as the reaction slows. Interval → chord; instant → tangent.

Notes · 3 of 4

Required practical: the effect of concentration

Same reactants, stronger acid — the race gets shorter.

Trilogy’s rates practical compares how fast a reaction runs at different concentrations, by either the disappearing-cross or the gas-syringe method. Disappearing cross: draw a cross on paper, stand a beaker of sodium thiosulfate solution over it, add hydrochloric acid, start the stopwatch, and stop when the cloudy precipitate hides the cross. Repeat with the same volumes at different concentrations.

The independent variable is the concentration; the dependent variable is the time for the cross to vanish (or the gas volume after a fixed time); control variables include the total volumes used, the mass and surface area of any solid, and the temperature. A shorter time means a faster rate, so results are compared as 1/time: if doubling the concentration roughly doubles 1/time, rate is proportional to concentration.

Typical disappearing-cross results
Concentration (mol/dm³)Time for cross to vanish (s)1/time (1/s)
0.5900.011
1.0450.022
1.5300.033
2.0220.045

Worked example — reading the pattern

From the table: 0.5 mol/dm³ gives 1/90 = 0.011 per second; 1.0 gives 1/45 = 0.022. Doubling the concentration has doubled 1/time, so the rate is proportional to concentration. Evaluation marks come from the controls — if temperature or surface area drift between runs, the comparison wobbles.

Notes · 4 of 4

Reversible reactions and dynamic equilibrium

A reaction that runs both ways can settle at a standoff.

Some reactions run in both directions. Heat blue hydrated copper(II) sulfate and it releases water vapour, leaving white anhydrous powder; add water and the blue returns, with the tube warming. The symbol ⇌ marks a reversible reaction. Forward and reverse reactions can run at the same time, and in a closed system (nothing escapes) they eventually run at the same rate — dynamic equilibrium. “Dynamic” means both reactions keep going; “equilibrium” means the amounts of reactants and products no longer change.

(Higher) Change the conditions and the balance tips. Le Chatelier-style rule: the equilibrium shifts to oppose the change. Add more of a reactant → the system consumes it, shifting to the products. Increase the pressure on a gas equilibrium → the system shifts to the side with fewer gas molecules, because fewer molecules lowers the pressure. For N₂(g) + 3H₂(g) ⇌ 2NH₃(g), four gas molecules sit on the left and two on the right, so extra pressure pushes the equilibrium right, towards more ammonia. A catalyst, note, speeds both directions equally — it reaches equilibrium faster without moving its position.

Worked example — predicting a shift

Q: More hydrogen is added to the N₂ + 3H₂ ⇌ 2NH₃ mixture at constant volume. What happens? A: The equilibrium opposes the change by removing the extra hydrogen, so it shifts right, making more ammonia until a new equilibrium forms. Name the change, state the opposition, name the direction — the three-move answer.

Revise

Key terms

The words examiners expect you to use precisely.

Rate of reaction
How fast a reactant is used up or a product is formed, measured as quantity change divided by time.
Collision theory
Reactions occur when particles collide with at least the activation energy; rate depends on collision frequency and energy.
Activation energy
The minimum energy colliding particles need for a reaction to succeed.
Catalyst
A substance that speeds a reaction by providing a lower-activation-energy route and is unchanged in mass and chemistry at the end.
Surface-area-to-volume ratio
How exposed a solid is; powders have a much higher ratio than lumps, giving faster rates.
Gas syringe
A sealed syringe used to collect and measure the volume of gas made by a reaction.
Show 4 more key terms
Tangent
A line touching a curve at one point; its gradient gives the instantaneous rate at that moment.
Reversible reaction
A reaction that runs in both directions, marked with the ⇌ symbol.
Closed system
A setup in which no reactants or products can escape — the only place dynamic equilibrium can form.
Dynamic equilibrium
The state in a closed system where forward and reverse reactions run at equal rates, so amounts stay constant.

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Quoting a rate without units

    “The rate is 1.6” is meaningless — 1.6 what?

    Instead: Always attach the unit: 1.6 cm³/s, 0.012 g/s, mol/s.

  • Mistake: Saying higher temperature works because particles are “bigger” or “more reactive”

    Particle size never changes with temperature.

    Instead: Particles move faster, colliding more often and more energetically.

Show 10 more mistakes
  • Mistake: Treating a catalyst as a reactant that gets used up

    Catalysts emerge chemically unchanged with the same mass.

    Instead: They lower the activation energy without being consumed.

  • Mistake: Claiming a catalyst increases the amount of product

    Catalysts change how fast equilibrium is reached, not how much product forms.

    Instead: Same final yield, faster arrival — and no shift in the equilibrium position.

  • Mistake: Reading a flattened curve as “the reaction continues slowly”

    A flat curve has zero gradient — zero rate.

    Instead: The reaction has finished because a reactant ran out.

  • Mistake: Using the mean rate as the rate at an instant

    The interval average hides the slowing.

    Instead: Instantaneous rate needs the gradient of a tangent at that time.

  • Mistake: Treating a longer disappearing-cross time as a faster reaction

    It is exactly backwards.

    Instead: Shorter time = faster rate; compare with 1/time so bigger means faster.

  • Mistake: Changing the solid’s surface area in the concentration practical

    Surface area is its own rate factor — it confounds the test.

    Instead: Control the solid’s mass and form (same powder, same mass) in every run.

  • Mistake: Saying equilibrium means reactants and products are equal

    Equal amounts are not required — only equal rates.

    Instead: At dynamic equilibrium the forward and reverse rates match; the amounts sit wherever the balance lies.

  • Mistake: Looking for equilibrium in an open beaker

    Gas escaping means the reverse reaction cannot keep pace.

    Instead: Dynamic equilibrium needs a closed system.

  • Mistake: (Higher) Shifting an equilibrium towards the side with more gas molecules under pressure

    More molecules would raise the pressure further.

    Instead: The equilibrium opposes the pressure rise by moving to fewer gas molecules.

  • Mistake: (Higher) Moving the equilibrium with a catalyst

    Catalysts speed forward and reverse equally.

    Instead: Equilibrium is reached sooner but its position is unchanged.

Check yourself

Quick quiz

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Explain rates, collision theory and the four factors

A reaction produces 48 cm³ of gas in 30 s. The mean rate is

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Practise

Topical questions

12 exam-style questions with model answers and mark schemes.

A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.

Practise topical questions

Exam practice

Practice paper

A 30-mark paper in the style of a Combined Science paper, with a separate mark scheme. Give yourself 40 min.

Question paper

Chapter 17 Practice Paper

30 marks · 40 min · 5 pages

6 multiple-choice questions and structured questions with answer lines. Mean rates and units, collision theory, the four rate factors, catalysts, rate graphs and tangents, the concentration required practical, reversible reactions and Higher-tier equilibrium shifts.

Mark scheme

PRO

Chapter 17 Practice Paper — mark scheme

Answers · Marking points · 3 pages

Model answers with a mark for each creditworthy point — for marking at home or in class.

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How does this chapter fit the real exams?

Chemistry Paper 1

1 h 15 · 70 marks (Trilogy)

Atomic structure, bonding, quantitative chemistry, chemical and energy changes (chapters 11–16)

Chemistry Paper 2

1 h 15 · 70 marks (Trilogy)

Rates, organic chemistry, analysis, atmosphere and resources (chapters 17–20)

Tiers

Foundation (grades 1-1 to 5-5) · Higher (4-3 to 9-9)

Two grades are awarded together; the 21 required practicals are examined on the written papers

Want a full paper? Try the Biology Paper 1-style (Foundation), Biology Paper 1-style (Higher), Biology Paper 2-style (Foundation), Biology Paper 2-style (Higher), Chemistry Paper 1-style (Foundation), Chemistry Paper 1-style (Higher), Chemistry Paper 2-style (Foundation), Chemistry Paper 2-style (Higher), Physics Paper 1-style (Foundation), Physics Paper 1-style (Higher), Physics Paper 2-style (Foundation), Physics Paper 2-style (Higher), Required practicals practice sets.

Questions

Frequently asked questions

Is the Haber process in Combined Science?

No — the Haber process, percentage yield and atom economy belong to separate GCSE Chemistry. Combined stops at reversible reactions, dynamic equilibrium and Higher-tier equilibrium shift predictions.

Which required practical lives in this chapter?

The concentration practical: comparing reaction rates at different concentrations with the disappearing-cross or gas-syringe method, controlling temperature, volumes and the solid’s surface area, and comparing runs with 1/time.

How do I answer every “explain the rate” question?

Collision theory template: name the factor, state what it does to collision frequency or energy, conclude that more successful collisions happen each second, so the rate rises.

What units should rates have?

Whatever matches the quantity: cm³/s for gas volume, g/s for mass change, mol/s for moles — always quantity per time.

Which maths skills appear in this chapter?

Mean rates from data, gradients and tangents for instantaneous rates, 1/time comparisons, and simple subtraction for interval rates.

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Chapter 18: Crude oil, fuels and alkenes

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