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Chapter 25Particle model and atomic structureAQA Trilogy · Edexcel · OCR GatewayFoundation + HigherDouble awardNot yet teacher-reviewed

GCSE Combined Science Particle model and density revision

Everything is particles in motion: locked in a lattice, sliding past each other, or flying free. The particle model explains states, changes of state, why density packs mass into volume, why gas pressure pushes on every wall it meets — and why a bike pump gets warm. Master ρ = m/V, the displacement practical and the Higher latent-heat and pressure equations.

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Not yet teacher-reviewed. Written by the QuizQuip team against the DfE GCSE combined science subject content; a teacher has not checked it yet. Spotted a mistake? Tell us

Overview

What you’ll learn

  • Describe the arrangement and motion of particles in solids, liquids and gases.
  • Explain changes of state and internal energy in terms of the particle model.
  • Calculate density in kg/m³ and g/cm³ and convert fluently between the units.
  • Write up the density required practical for regular solids, irregular solids and liquids.
  • Use E = mL for melting and boiling, and read heating curves (Higher).
  • Explain gas pressure, use p₁V₁ = p₂V₂ (Higher) and explain why pumps warm up.

Specification checklist (AQA Trilogy 8464 · Edexcel 1SC0 · OCR Gateway J250)

Statements are paraphrased from the shared DfE combined science subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. This chapter covers only what Combined Science (double award) examines — separate-science extras live on the GCSE Biology, Chemistry and Physics hubs. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.

Foundation — every student

  • 25.1Describe the particle model: solids have particles vibrating about fixed positions in a regular arrangement, liquid particles are close together but free to move past one another, and gas particles are far apart and move rapidly in random directions.
  • 25.2Describe changes of state (melting, freezing, evaporation, boiling, condensation, sublimation) as physical changes that conserve mass, and explain internal energy as the total kinetic and potential energy stored by the particles.
  • 25.3Calculate density using ρ = m/V, in kg/m³ and g/cm³, and convert between them (1 g/cm³ = 1000 kg/m³).
  • 25.4Carry out the density required practical: measure the density of a regular solid from its dimensions, of an irregular solid by displacement of water (displacement can or measuring cylinder) and of a liquid using a balance and measuring cylinder.
  • 25.5Explain heating curves and cooling curves: temperature rises while one state is heated, and holds constant during a change of state because the energy supplied goes into changing particle arrangements rather than raising temperature.
  • 25.7Explain gas pressure as the result of particles colliding with the walls of a container, and explain why heating a gas in a sealed, rigid container raises the pressure (faster particles collide harder and more often).
  • 25.9Explain how doing work on a gas (compressing it quickly, as in a bike pump) raises its internal energy and its temperature.

Higher — Higher tier only

  • 25.6Calculate the energy for a change of state using E = m L, for both fusion (melting) and vaporisation (boiling); specific latent heat is the energy needed to change the state of 1 kg with no change in temperature.
  • 25.8Calculate changes in gas pressure and volume at constant temperature using p₁ V₁ = p₂ V₂, and explain qualitatively why reducing the volume raises the pressure.

Key points

  1. 1Solids: particles vibrate about fixed positions; liquids: close but sliding past each other; gases: far apart, fast, random motion.
  2. 2Changes of state are physical changes — the mass stays exactly the same. Internal energy = total kinetic + potential energy stored by the particles.
  3. 3Density is mass per volume: ρ = m/V. Water is 1000 kg/m³ = 1 g/cm³; to convert g/cm³ → kg/m³, multiply by 1000.
  4. 4Required practical: density from dimensions (regular solid), water displacement (irregular solid) and balance + measuring cylinder (liquid).
  5. 5On a heating curve, flat sections = change of state at constant temperature — the energy breaks particle bonds instead of raising temperature.
  6. 6E = m L (Higher): energy to melt or boil mass m; water's latent heat of vaporisation (2 260 000 J/kg) dwarfs that of fusion — steam scalds because it releases it on condensing.
  7. 7Gas pressure comes from billions of particle collisions on the container walls every second; heating a sealed gas raises pressure.
  8. 8p₁V₁ = p₂V₂ at constant temperature (Higher); compressing a gas quickly does work on it — that is why a bike pump barrel warms.

Notes · 1 of 4

Particles, states and internal energy

Three arrangements, six changes of state, one energy account.

The particle model pictures matter as tiny moving particles. In a solid they are packed in a regular pattern and vibrate about fixed positions — a fixed shape and volume. In a liquid they are still close together but slide past one another, so the substance flows and takes its container's shape. In a gas the particles are far apart and fly in random directions at high speed, filling whatever space they are given and easily squeezed into less.

The six changes of state — melting, freezing, evaporating, boiling, condensing and sublimating — are physical changes: the particles themselves never change, only their arrangement, so the mass is exactly conserved. Internal energy is the account book of the particles: the sum of their kinetic stores (how fast they move or vibrate) and potential stores (the energy in their arrangements and the forces between them). Heating adds to both; a change of state spends the energy on the potential store alone, which is why the temperature holds steady while, say, ice melts.

The three states compared
PropertySolidLiquidGas
ArrangementRegular, fixed positionsClose, disorderedFar apart, random
MotionVibrating in placeSliding past neighboursFast, random, straight lines
Shape / volumeFixed / fixedTakes container shape / fixedFills all space offered
CompressibilityAlmost noneAlmost noneEasily compressed

Worked example — reading a heating curve

Q: A substance is heated steadily. Its temperature climbs, then holds at −7 °C for two minutes, then climbs again, then holds at 58 °C, then climbs. Interpret the flat sections. A: The flat section at −7 °C is melting — energy is weakening the rigid particle arrangement, so the temperature does not move. The flat section at 58 °C is boiling — the same story for liquid → gas. Rising sections are single states being warmed.

Notes · 2 of 4

Density and the required practical

How tightly a substance packs its mass — and how to measure it.

Density is the mass packed into each unit of volume: ρ = m/V, with ρ in kg/m³ when m is in kilograms and V in cubic metres, or in g/cm³ for grams and cubic centimetres. The conversion: 1 g/cm³ = 1000 kg/m³ (a cubic metre holds a million cubic centimetres, and a kilogram is a thousand grams). Water sits at 1000 kg/m³; a cube of side 0.20 m with mass 21.6 kg has V = 0.20³ = 0.008 m³, so ρ = 21.6 ÷ 0.008 = 2700 kg/m³ — aluminium.

Required practical — density. For a regular solid (a cube or cuboid), measure each side with a ruler and compute the volume, then divide the balance-measured mass by it. For an irregular solid, lower it into a displacement can (or a measuring cylinder of water) and read the volume of water pushed out — a 178 g object that displaces 20 cm³ has ρ = 178 ÷ 20 = 8.9 g/cm³, the density of copper. For a liquid, weigh the empty measuring cylinder, add the liquid, read the volume at eye level, and subtract: 96 g of liquid filling 100 cm³ gives ρ = 0.96 g/cm³. Read the volume scale at the bottom of the meniscus and repeat for a mean.

Practical pitfalls

Small errors in volume are magnified for small objects — use a micrometer for a wire's diameter, and objects big enough to displace a readable volume. Wait for the displacement can to stop dripping before reading. Zero the balance. And never mix unit families: grams with cm³, kilograms with m³.

Notes · 3 of 4

Latent heat: the hidden energy of state changes (Higher)

Why boiling dry takes far more energy than melting.

During a change of state the temperature does not budge — yet you must keep supplying energy. The energy goes into changing the particle arrangement, not their speeds. The specific latent heat of fusion (L) is the energy needed to melt 1 kg of a substance at its melting point; the specific latent heat of vaporisation is the energy to boil 1 kg away. The equation is E = m L. Melting 0.25 kg of ice (L = 334 000 J/kg) takes E = 0.25 × 334 000 = 83 500 J.

Vaporisation's latent heat is always far larger than fusion's — breaking a liquid apart completely costs much more than loosening a solid. Water's values: 334 000 J/kg to melt, 2 260 000 J/kg to boil. That asymmetry is why a steam scald is vicious: when steam condenses on skin it releases its full latent heat — for 0.030 kg of steam that is 0.030 × 2 260 000 = 67 800 J delivered at 100 °C, on top of the cooling the water would do afterwards.

Worked example — boiling away a kettle's drips

Q: A 2.0 kW kettle is left boiling. How much energy turns 0.025 kg of water to steam (L = 2 260 000 J/kg), and for how long? A: E = mL = 0.025 × 2 260 000 = 56 500 J. Time = E ÷ P = 56 500 ÷ 2000 = 28.25 s ≈ 28 s, assuming all the electrical energy reaches the water. State the assumption — it carries the evaluation mark.

Notes · 4 of 4

Gas pressure and the piston

Collisions push; temperature, volume and work decide how hard.

A gas presses on every wall of its container because its particles are colliding with it billions of times a second, each collision delivering a tiny push. The summed pushes per unit area are the gas pressure. Heating a gas in a sealed, rigid container makes the particles move faster, so they collide harder and more often — the pressure rises. That is the physics behind warnings never to incinerate a sealed aerosol can.

Squeeze the gas instead and the particles are crowded into a smaller volume, so they hit the walls more often — pressure rises. At constant temperature the link is exact: p₁V₁ = p₂V₂. A gas at 160 kPa occupying 3.0 m³, compressed to 1.2 m³, ends at p₂ = (160 × 3.0) ÷ 1.2 = 400 kPa. In the other direction, 120 kPa of gas expanding from 6.0 m³ to 9.0 m³ falls to (120 × 6.0) ÷ 9.0 = 80 kPa.

Doing work on a gas changes things once more. Push a syringe plunger quickly and your muscles transfer energy to the gas particles — their internal energy rises and so does the temperature. That is why a bike pump warms as you inflate a tyre, and why fast compressions break the constant-temperature rule that p₁V₁ = p₂V₂ relies on. Compress slowly, letting heat escape, and the relation holds.

Worked example — the higher-pressure tyre (Higher)

Q: Air at 250 kPa occupies 0.80 m³. It is compressed slowly (constant temperature) to 0.50 m³. Find the new pressure and explain the rise in particle terms. A: p₂ = (250 × 0.80) ÷ 0.50 = 400 kPa. The same number of particles now bangs against the walls more often and from a smaller area, so the pressure per unit area climbs.

Revise

Key terms

The words examiners expect you to use precisely.

Particle model
The model of matter as tiny moving particles whose arrangement and motion explain the states of matter.
Internal energy
The total kinetic and potential energy stored by the particles of a system.
Change of state
A physical change — melting, freezing, evaporating, boiling, condensing or sublimating — that conserves mass.
Density
Mass per unit volume, ρ = m/V, in kg/m³ or g/cm³ (1 g/cm³ = 1000 kg/m³).
Displacement
The volume of fluid pushed aside by a submerged object — how irregular volumes are measured.
Displacement (eureka) can
A brim-full can with a spout that delivers exactly the volume displaced by a lowered object.
Show 4 more key terms
Specific latent heat of fusion
The energy needed to melt 1 kg of a substance at its melting point with no temperature change.
Specific latent heat of vaporisation
The energy needed to turn 1 kg of a liquid into vapour at constant temperature; far larger than fusion's value.
Gas pressure
The force per unit area a gas exerts on its container, produced by countless particle collisions.
p₁V₁ = p₂V₂
The constant-temperature rule linking a gas's pressure and volume across a change (Higher tier).

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Assuming the bigger object is always the denser one

    Density divides by volume — a big low-mass object can be very light per cm³.

    Instead: Compare mass-to-volume ratios, not raw sizes: a 21.6 kg aluminium cube is less dense than a 1 kg lead brick.

  • Mistake: Converting g/cm³ to kg/m³ by dividing by 1000

    The conversion runs the other way — a kg/m³ value is 1000 times its g/cm³ value.

    Instead: 1 g/cm³ = 1000 kg/m³: multiply by 1000 going to kg/m³ (19.3 g/cm³ = 19 300 kg/m³).

Show 10 more mistakes
  • Mistake: Mixing grams with cubic metres in ρ = m/V

    The answer comes out wrong by factors of thousands.

    Instead: Keep families together: g with cm³, kg with m³.

  • Mistake: Saying mass is lost when ice melts

    Changes of state rearrange particles; none are created or destroyed.

    Instead: Mass is conserved in every change of state — 0.40 kg of ice makes 0.40 kg of water.

  • Mistake: Expecting the thermometer to keep rising during melting

    The supplied energy goes into breaking the arrangement, not speeding particles up.

    Instead: A flat section on the heating curve means a change of state at constant temperature.

  • Mistake: Using ΔE = mcΔθ for a change of state

    That equation changes temperature; state changes happen with none.

    Instead: State changes use E = mL; temperature changes use ΔE = mcΔθ.

  • Mistake: Using the latent heat of fusion for boiling

    Fusion is for melting; vaporisation is the much larger boiling value.

    Instead: Water: 334 000 J/kg to melt, 2 260 000 J/kg to vaporise — pick by direction of change.

  • Mistake: Attributing gas pressure to the gas's weight

    Pressure acts sideways and upwards on all walls equally; weight acts down.

    Instead: Pressure is particle collisions per unit area on every wall.

  • Mistake: Saying heated gas particles expand

    Particles never grow — they move faster.

    Instead: Heating raises particle speed, so collisions with fixed walls come harder and more often: pressure rises.

  • Mistake: Swapping V₁ and V₂ in p₁V₁ = p₂V₂

    Mixing before and after values scrambles the answer.

    Instead: Group the before-values on one side (p₁V₁) and the after-values on the other (p₂V₂).

  • Mistake: Reading the displacement can before it stops dripping

    The collected volume is then short of the object's true volume.

    Instead: Wait for the spout to stop, then read the measuring cylinder at the meniscus.

  • Mistake: Claiming air has no mass

    A 30 m³ bedroom holds about 36 kg of air at 1.2 kg/m³.

    Instead: Gases are matter: m = ρV works for air as for anything else.

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Topical questions

12 exam-style questions with model answers and mark schemes.

A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.

Practise topical questions

Exam practice

Practice paper

A 30-mark paper in the style of a Combined Science paper, with a separate mark scheme. Give yourself 40 min.

Question paper

Chapter 25 Practice Paper

30 marks · 40 min · 6 pages

6 multiple-choice questions and structured questions with answer lines. The particle model and states of matter, changes of state and internal energy, density and the density required practical, heating curves, specific latent heat (Higher), gas pressure from particle collisions, pressure–volume calculations (Higher) and work done on a gas.

Mark scheme

PRO

Chapter 25 Practice Paper — mark scheme

Answers · Marking points · 3 pages

Model answers with a mark for each creditworthy point — for marking at home or in class.

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How does this chapter fit the real exams?

Physics Paper 1

1 h 15 · 70 marks (Trilogy)

Energy, electricity, particle model, atomic structure (chapters 21–26)

Physics Paper 2

1 h 15 · 70 marks (Trilogy)

Forces, waves, magnetism and electromagnetism (chapters 27–30)

Tiers

Foundation (grades 1-1 to 5-5) · Higher (4-3 to 9-9)

Two grades are awarded together; the 21 required practicals are examined on the written papers

Want a full paper? Try the Biology Paper 1-style (Foundation), Biology Paper 1-style (Higher), Biology Paper 2-style (Foundation), Biology Paper 2-style (Higher), Chemistry Paper 1-style (Foundation), Chemistry Paper 1-style (Higher), Chemistry Paper 2-style (Foundation), Chemistry Paper 2-style (Higher), Physics Paper 1-style (Foundation), Physics Paper 1-style (Higher), Physics Paper 2-style (Foundation), Physics Paper 2-style (Higher), Required practicals practice sets.

Questions

Frequently asked questions

How do I convert between g/cm³ and kg/m³?

Multiply by 1000 to go from g/cm³ to kg/m³, divide to come back. Water's 1 g/cm³ becomes 1000 kg/m³, and gold's 19.3 g/cm³ becomes 19 300 kg/m³. The reason: a cubic metre is a million cubic centimetres while a kilogram is only a thousand grams.

What is the best route through the density practical?

Regular solid: ruler for dimensions, volume from geometry, mass from a balance. Irregular solid: displacement can or measuring cylinder — the water pushed out equals the object's volume. Liquid: weigh the empty measuring cylinder, add liquid, read volume at the meniscus, subtract the empty mass. Then ρ = m/V in matched units.

Why does temperature stop rising during melting or boiling?

The energy you supply goes into the particles' potential store — loosening and separating the arrangement — rather than their kinetic store. With average particle speed unchanged, the thermometer reads steady until the change of state is complete. That is the flat section of the heating curve.

Why is boiling so much more expensive in energy than melting?

Water's latent heat of vaporisation (2 260 000 J/kg) is nearly seven times its latent heat of fusion (334 000 J/kg). Melting loosens a lattice; boiling separates the particles completely against their attractions — and that is why steam scalds so badly, releasing all of it as it condenses.

When do I use p₁V₁ = p₂V₂?

For a fixed mass of gas at constant temperature (Higher tier). Group the before-values (p₁V₁) and after-values (p₂V₂), then solve. It assumes slow changes — compress quickly and the work done on the gas raises its temperature, breaking the relation and warming the pump.

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