Overview
What you’ll learn
- Define dynamic equilibrium and state the conditions (closed system) it needs.
- Predict (Higher) how concentration, pressure and temperature shifts move an equilibrium, using Le Chatelier’s principle.
- Describe the Haber process, its catalyst, and the compromise behind 450 °C and 200 atm.
- Calculate percentage yield and, (Chemistry only) atom economy, and explain why they differ.
- Describe (Chemistry only) how NPK fertiliser salts are made, in the lab and industrially.
Specification checklist (AQA 8462 · Edexcel 1CH0 · OCR Gateway J248)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only, and statements badged Chemistry only are examined in separate (triple) Chemistry, not Combined Science. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 13.1Describe reversible reactions and dynamic equilibrium: in a closed system, when the forward and reverse reactions happen at the same rate, the concentrations of reactants and products stay constant.
- 13.4Describe the Haber process: purified nitrogen and hydrogen passed over an iron catalyst at about 450 °C and about 200 atmospheres, ammonia condensed out as a liquid and unreacted gases recycled.
- 13.5Calculate the percentage yield of a reaction from actual and theoretical yields, and explain why a reversible reaction never converts all reactants to product.Chemistry only
- 13.6Define and calculate (Chemistry only) the atom economy of a reaction: the percentage of the mass of the products that is the desired product; compare routes and explain why industry prefers high atom economy, including finding uses for co-products.Chemistry only
- 13.7Describe (Chemistry only) NPK fertilisers as formulations of nitrogen, phosphorus and potassium compounds; explain how ammonium salts are made by neutralising acids with ammonia and how phosphate rock is treated with nitric, sulfuric or phosphoric acid to give soluble salts.Chemistry only
- 13.8Compare (Chemistry only) making a fertiliser salt in a school laboratory (small-scale batch, slower, dilute solutions) with industrial production (large-scale continuous, faster per tonne), and evaluate the choices.Chemistry only
Higher — Higher tier only
- 13.2State (Higher) Le Chatelier’s principle: when a change is made to the conditions of a system at equilibrium, the position of equilibrium shifts to oppose the change.
- 13.3Predict (Higher) the effect of changing concentration, pressure (for gases) or temperature on the position of equilibrium, and explain why a catalyst changes the rate but not the position.
Key points
- 1A reversible reaction goes forwards and backwards; its symbol arrow is ⇌.
- 2Dynamic equilibrium needs a closed system: forward rate = reverse rate, concentrations constant (not equal).
- 3Le Chatelier (Higher): change the conditions and the equilibrium shifts to oppose the change.
- 4More pressure → shifts to the side with fewer moles of gas; more temperature → shifts in the endothermic direction.
- 5A catalyst speeds forward and reverse equally — faster equilibrium, same position.
- 6Percentage yield = actual ÷ theoretical × 100 — reversible reactions never give 100%.
- 7Atom economy (Chemistry only) = Mr of desired product ÷ total Mr of all products × 100 — 100% with a single product.
- 8Haber: N₂ + 3H₂ ⇌ 2NH₃, iron catalyst, 450 °C (yield vs rate compromise), 200 atm, ammonia condensed, gases recycled.
Notes · 1 of 5
Reversible reactions and dynamic equilibrium
Both directions at once — until the two rates cancel out into a standoff.
A reversible reaction produces products that can react again to remake the reactants: A + B ⇌ C + D. The classic example is hydrated copper(II) sulfate: the blue crystals lose water on heating to leave white powder, and the white powder turns blue again when water is added. Equilibrium can only settle in a closed system — nothing added, nothing escaping. In an open beaker the escaping substance is lost and the reaction just runs one way.
Left alone in a closed system, the reaction reaches dynamic equilibrium: the forward and reverse reactions are still happening — that is the dynamic part — but at equal rates, so the amounts of reactants and products stop changing. Equal rates, not equal amounts: the equilibrium can sit far to one side. The position of equilibrium describes that balance — far right means mostly products, far left means mostly reactants.
Notes · 2 of 5
Le Chatelier’s principle (Higher)
Poke the equilibrium and it pushes back — predict the direction and you have the marks.
Le Chatelier’s principle: when the conditions of an equilibrium change, the position shifts to oppose the change. Concentration: add more reactant and the equilibrium shifts towards the products to use it up. Pressure (gases only): compressing the mixture shifts the equilibrium towards the side with fewer moles of gas, because fewer molecules lowers the pressure. Temperature: heating shifts the equilibrium in the endothermic direction to absorb the extra heat; cooling shifts it in the exothermic direction. For an exothermic forward reaction (like the Haber process), that means heating reduces the product yield — an awkward truth industry must design around.
A catalyst speeds up the forward and reverse reactions equally, so equilibrium is reached faster but the position does not move — the equilibrium amount of product is unchanged. And a warning for predictions: pressure has nothing to do with solids or pure liquids, so count only gaseous (or dissolved) moles on each side.
Notes · 3 of 5
The Haber process
Feeding the world with ammonia — one carefully designed compromise at a time.
The Haber process makes ammonia for fertilisers: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), with the forward reaction exothermic (heat released). Purified nitrogen (from air) and hydrogen (usually from natural gas) are passed over an iron catalyst at about 450 °C and 200 atmospheres. Only about a third of the mixture reacts each pass, so the ammonia is condensed to a liquid (it has a far higher boiling point than nitrogen or hydrogen) and the unreacted gases are recycled back over the catalyst. Recycling means that overall, most of the nitrogen and hydrogen eventually become ammonia.
Why 450 °C? A lower temperature would give a higher yield (the exothermic direction is favoured when you take heat away) — but the rate would be impossibly slow, even with the catalyst. A higher temperature gives a fast rate but a poor yield. 450 °C is a compromise — fast enough to be economic, with an acceptable yield. Similarly, 200 atm rather than 1000 atm: pressure favours the ammonia side (4 gas moles → 2), but very high pressure means expensive pumps, thick-walled vessels and safety risks. Another compromise.
Notes · 4 of 5
Percentage yield and atom economy
How much you actually got, versus where the atoms ended up.
Percentage yield = (actual yield ÷ theoretical yield) × 100. The theoretical yield comes from the balanced equation — the maximum possible mass of product. Real reactions rarely hit 100%: the reaction may be reversible (some product turns back), reactants may be impure, product is lost in transfers and purification, or side reactions make unwanted products. Note the difference between yield (how much you collected, in practice) and atom economy (Chemistry only): a purely theoretical measure of how much of the reactant mass ends up in the molecule you want — atom economy = (Mr of desired product ÷ sum of Mr of ALL products) × 100, using the balanced equation. A single-product reaction is automatically 100%.
Industry weighs both numbers: a route with low atom economy throws mass away as waste (cost, disposal, environmental impact), so chemists design high atom economy routes and find uses for co-products — selling the leftovers instead of paying to dump them. Chemistry only: the same logic explains why the Haber process is attractive — it has a single product, so its atom economy is 100% even though its percentage yield per pass is nothing like it.
Notes · 5 of 5
NPK fertilisers (Chemistry only)
Three elements, formulated into prills — mined, reacted and matched to the soil.
Plants need three main nutrients in fertiliser: nitrogen (N), phosphorus (P) and potassium (K). An NPK fertiliser is a formulation — a mixture blended to a deliberate recipe of several compounds, each chosen for its nutrient and its solubility, often with fillers that keep the prills free-flowing. Roots can only absorb nutrients dissolved in water, so every nutrient compound in the blend must be soluble.
- 1Nitrogen salts
Ammonia (from the Haber process) neutralises nitric acid to make ammonium nitrate, or sulfuric acid for ammonium sulfate: NH₃ + HNO₃ → NH₄NO₃. Both are soluble nitrogen sources.
- 2Phosphorus salts
Phosphate rock is mined but its phosphates are insoluble. Treating it with phosphoric acid gives soluble phosphates; nitric acid or sulfuric acid give other soluble phosphate/nitrate mixtures.
- 3Potassium salts
Potassium chloride and potassium sulfate are mined directly (as in the Yorkshire potash mines) and dissolve readily — no chemical conversion needed.
Making a fertiliser salt in the lab (ammonium sulfate is the usual example): a small batch, titrated to find the exact neutralisation point, with evaporation and crystallisation — slow and small-scale, but precise and safe. Industrial production is a continuous process: huge volumes of ammonia and acid stream through at controlled stoichiometry, making tonnes per hour far more cheaply per tonne. The lab optimises for care; the plant optimises for scale. (This chapter has no named required practical, but the fertiliser preparation is examined as a method question — learn the titrate-neutralise-evaporate sequence.)
Revise
Key terms
The words examiners expect you to use precisely.
- Reversible reaction
- A reaction where the products can react to reform the reactants (⇌).
- Closed system
- No substances can enter or leave — the precondition for a true equilibrium.
- Dynamic equilibrium
- Forward and reverse reactions occur at equal rates; concentrations stay constant.
- Position of equilibrium
- The balance between reactants and products at equilibrium — left (mostly reactants) to right (mostly products).
- Le Chatelier’s principle
- A change in conditions shifts the equilibrium to oppose the change (Higher).
- Haber process
- Industrial ammonia synthesis: N₂ + 3H₂ ⇌ 2NH₃ over an iron catalyst at ~450 °C and ~200 atm.
Show 6 more key termsShow fewer key terms
- Percentage yield
- Actual yield ÷ theoretical yield × 100.
- Atom economy
- Mr of desired product ÷ total Mr of all products × 100 — the fraction of reactant mass that ends up in the wanted product.
- NPK fertiliser
- A formulation supplying nitrogen, phosphorus and potassium in soluble compounds.
- Formulation
- A mixture made to a precise recipe with a designed purpose.
- Phosphate rock
- Mined mineral whose insoluble phosphates are acid-treated to make soluble fertiliser salts.
- Compromise conditions
- Industrial settings balancing yield, rate and cost rather than maximising any one.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Saying equilibrium means “the amounts of reactants and products are equal”.
Equal amounts is not the criterion.
Instead: At equilibrium the RATES of forward and reverse reactions are equal — the amounts are constant but usually unequal.
Mistake: Treating equilibrium as “both reactions have stopped”.
That would be static, not dynamic.
Instead: Dynamic: both reactions continue at equal rates, so nothing appears to change.
Show 10 more mistakesShow fewer mistakes
Mistake: Reaching equilibrium in an open beaker.
Escaping gas or vapour removes material — the balance never settles.
Instead: Dynamic equilibrium needs a CLOSED system; in open apparatus the reaction runs to completion one way.
Mistake: Claiming a catalyst shifts the equilibrium to make more product.
Catalysts change speed, never position.
Instead: A catalyst speeds forward and reverse equally — same equilibrium, reached faster.
Mistake: Saying higher pressure shifts equilibrium to the side with more gas moles.
That would add to the pressure problem.
Instead: The system opposes the change: higher pressure shifts to FEWER moles of gas.
Mistake: Counting solid or liquid moles when predicting a pressure effect.
Pressure barely affects condensed phases.
Instead: Count only gaseous moles (and dissolved species for concentration changes).
Mistake: Assuming raising temperature always raises the yield.
Direction depends on which way is endothermic.
Instead: Heating favours the ENDOTHERMIC direction — for an exothermic forward reaction (Haber), yield falls.
Mistake: Writing percentage yield as theoretical ÷ actual.
That gives a number over 100%.
Instead: Percentage yield = actual ÷ theoretical × 100.
Mistake: Confusing atom economy with percentage yield.
One is from the equation, the other from the experiment.
Instead: Atom economy: Mr of desired ÷ total Mr of products (theoretical). Yield: actual ÷ theoretical (practical).
Mistake: Insisting every reaction should have 100% atom economy.
Side products are often unavoidable.
Instead: Single-product reactions are 100%; otherwise chemists design routes around it and find uses for co-products.
Mistake: Saying ammonia is condensed “because it is the heaviest gas”.
Condensation is about boiling point, not mass.
Instead: Ammonia liquefies on cooling while N₂ and H₂ stay gaseous — far higher boiling point.
Mistake: Choosing insoluble salts for fertilisers.
Roots cannot absorb solids.
Instead: Fertiliser nutrients must be water-soluble so roots take up the dissolved ions.
Check yourself
Quick quiz
30 questions with instant explanations. About 5 minutes.
Question 1 of 3
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Define dynamic equilibrium
At dynamic equilibrium, the forward and reverse reactions
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier and Chemistry-only questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 13 Practice Paper
30 marks · 40 min · 6 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 13: reversible reactions and dynamic equilibrium, Le Chatelier’s principle (Higher), the Haber process and its compromise conditions, percentage yield, and (Chemistry only) atom economy and NPK fertilisers.
Mark scheme
PROChapter 13 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
1 h 45 · 100 marks
Chapters 1–11: atoms, bonding, quantitative, chemical and energy changes
Paper 2
1 h 45 · 100 marks
Chapters 12–18: rates, organic, analysis, atmosphere, resources
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content; a periodic table is printed
Want a full paper? Try the Paper 1-style (Foundation), Paper 1-style (Higher), Paper 2-style (Foundation), Paper 2-style (Higher), Required practicals practice sets.
Questions
Frequently asked questions
How do I predict any equilibrium shift?
Ask what the system must do to oppose the change. More pressure → go to fewer gas moles. More heat → go the endothermic way. More reactant → use it up (shift right). Catalyst → no shift at all, just a faster arrival.
Why does the Haber process not use the temperature that maximises yield?
Because at low temperature the rate collapses — you would wait forever for the equilibrium ammonia, even with the catalyst. 450 °C trades a little yield for a workable production rate. Time is money in industry.
What is the difference between yield and atom economy?
Yield is practical: what you collected versus what the equation promised. Atom economy is theoretical: what fraction of the product mass is the molecule you actually want. A reaction can be 100% atom economy and 30% yield — or the reverse.
Why must fertiliser salts be soluble?
Plant roots absorb nutrients as dissolved ions in soil water. That is why insoluble phosphate rock is acid-treated, and why NPK formulations choose soluble compounds like ammonium nitrate and potassium chloride.
Does QuizQuip have any connection to the exam boards?
No. AQA, Pearson Edexcel and OCR are named only to identify the specifications this content supports. QuizQuip is not affiliated with, endorsed by, or connected to AQA, Pearson Edexcel or OCR, and no past-paper or specimen material is reproduced.
Which parts of this chapter are Higher tier or Chemistry only?
Le Chatelier’s principle and predicting shifts are Higher tier. Atom economy, NPK fertilisers and the lab-versus-industrial comparison are separate-science (Chemistry only) content — Combined Science students can skip those sections.
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Chapter 14: Crude oil, fuels and cracking