Overview
What you’ll learn
- Write and balance symbol equations, including state symbols, without changing any formula.
- Explain why mass is always conserved in a reaction and what makes it appear not to be in an open flask.
- Calculate relative formula masses from atomic masses, including brackets in formulae.
- Deduce empirical formulae from mass or percentage data (Higher).
- Write ionic equations with spectator ions cancelled (Higher) and describe measurement uncertainty.
Specification checklist (AQA 8462 · Edexcel 1CH0 · OCR Gateway J248)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only, and statements badged Chemistry only are examined in separate (triple) Chemistry, not Combined Science. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 5.1Write word equations and balanced symbol equations for reactions, using chemical formulae correctly, including the diatomic elements H₂, N₂, O₂, F₂, Cl₂, Br₂ and I₂.
- 5.2Balance symbol equations by placing whole-number coefficients, understanding that balancing conserves the number of atoms of each element and never changes a formula.
- 5.3Use state symbols (s), (l), (g) and (aq) in equations and state what each represents.
- 5.4Apply the law of conservation of mass: the total mass of the products of a reaction equals the total mass of the reactants, because atoms are only rearranged.
- 5.5Explain apparent mass changes in non-enclosed systems: mass seems to fall when a gaseous product escapes and rises when a gas from the air is absorbed by the reaction mixture.
- 5.6Calculate the relative formula mass (Mr) of a compound from the relative atomic masses (Ar) of its elements.
- 5.7Deduce the empirical formula of a compound from the relative numbers of atoms present or from a model or diagram, and vice versa.
- 5.9Describe the uncertainty of a measurement: a reading is uncertain by half the resolution of the instrument, and repeats give a mean and range that describe the uncertainty of a result.
Higher — Higher tier only
- 5.11Deduce an empirical formula from the masses or percentage composition of each element in the compound, dividing each mass by its relative atomic mass (Higher-tier calculation).
- 5.8Write ionic equations for reactions between ions in solution, including the cancellation of spectator ions, and balance them.
- 5.10Interpret balanced equations quantitatively: the coefficients give the ratio of moles reacting and forming, so the proportions of reactants and products can be calculated.
Key points
- 1A balanced equation has equal numbers of every atom on both sides — balance with coefficients, never by altering a formula.
- 2State symbols: (s) solid, (l) liquid, (g) gas, (aq) dissolved in water (aqueous).
- 3Conservation of mass: atoms are rearranged, never created or destroyed, so total reactant mass = total product mass.
- 4In an open flask, mass appears to fall when a gas escapes (e.g. CO₂ from carbonate + acid) and to rise when a gas is taken in (e.g. magnesium burning, gaining oxygen).
- 5Mr = the sum of the Ar values in a formula; brackets multiply everything inside (Ca(OH)₂: 40 + 2 × 17 = 74).
- 6Empirical formula (Higher): divide each element’s mass by its Ar, then divide by the smallest to get the ratio.
- 7Ionic equations (Higher) show only the particles that actually react; spectator ions are cancelled.
- 8A measurement is uncertain by about half the resolution of the instrument; repeated readings are summarised by their mean and range.
Notes · 1 of 7
From words to formulae
Seven diatomic elements, correct formulae, then the equation writes itself.
A chemical equation is a sentence: reactants on the left, products on the right, an arrow meaning “reacts to form”. Writing one well demands correct formulae first. The traps to memorise: hydrogen, nitrogen, oxygen, fluorine, chlorine, bromine and iodine exist as diatomic molecules (H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂), and ionic compounds must be charge-neutral — calcium hydroxide is Ca(OH)₂ because two 1− hydroxides balance one 2+ calcium. Sodium plus water is “sodium + water → sodium hydroxide + hydrogen” as words; as formulae it becomes 2Na + 2H₂O → 2NaOH + H₂ once balanced.
Notes · 2 of 7
Balancing: coefficients, not formula changes
Big numbers in front adjust counts; the small subscripts inside a formula are untouchable.
Balancing adds coefficients — the large numbers in front of formulae — until each element has equal counts on both sides. A reliable method: balance metals first, then non-metals, then hydrogen, then oxygen (hydrogen and oxygen usually appear in several places, so save them for last). Check by listing every element’s totals. For CH₄ + O₂ → CO₂ + H₂O: carbon balances 1:1; four hydrogens need 2H₂O; those bring two oxygens, which with CO₂’s two make four, so 2O₂: CH₄ + 2O₂ → CO₂ + 2H₂O.
| Reaction | Balanced equation |
|---|---|
| Magnesium burning | 2Mg + O₂ → 2MgO |
| Aluminium burning | 4Al + 3O₂ → 2Al₂O₃ |
| Thermal decomposition of calcium carbonate | CaCO₃ → CaO + CO₂ |
| Calcium + water | Ca + 2H₂O → Ca(OH)₂ + H₂ |
| Neutralisation of NaOH by HCl | NaOH + HCl → NaCl + H₂O |
The coefficients also carry the ratio of moles: in 2Mg + O₂ → 2MgO, two moles of magnesium react with one of oxygen to give two of magnesium oxide. That ratio is the engine of all the reacting-mass work in the next chapter.
Notes · 3 of 7
Conservation of mass — and vanishing gas
No atom ever disappears; sometimes it just leaves the beaker.
The law of conservation of mass says the total mass of products equals the total mass of reactants: reactions only rearrange atoms. In a sealed flask, a balance confirms it every time. In an open vessel, the balance can lie. When calcium carbonate fizzes with acid, CO₂ bubbles away — the flask loses exactly the mass of gas that escaped. When magnesium burns in air, oxygen joins the solid, and the ash of magnesium oxide outweighs the original ribbon. Neither reaction breaks the law; the system just traded matter with the air.
The reverse case matters too: burning 2.4 g of magnesium in a crucible can leave more than 2.4 g of white powder, because oxygen atoms from the air became part of the product. 2.4 g Mg contains 0.1 mol of Mg atoms; 0.1 mol of MgO has mass 4.0 g, and the extra 1.6 g is exactly the oxygen gained (0.1 mol × 16 g/mol).
Notes · 4 of 7
Relative formula mass (Mr)
Add up the atomic masses the formula lists — brackets multiply everything inside.
The relative atomic mass (Ar) of an element is its average atomic mass compared with carbon-12 — the number printed on the periodic table. The relative formula mass (Mr) of a compound is the Ar values of its formula added together. Water: (2 × 1) + 16 = 18. Carbon dioxide: 12 + (2 × 16) = 44. Magnesium oxide: 24 + 16 = 40. Brackets multiply: Ca(OH)₂ = 40 + 2 × (16 + 1) = 74, and (NH₄)₂SO₄ = 2 × (14 + 4) + 32 + 4 × 16 = 132.
| Element | Ar | Element | Ar |
|---|---|---|---|
| H | 1 | O | 16 |
| C | 12 | Na | 23 |
| N | 14 | Mg | 24 |
| Ca | 40 | S | 32 |
Notes · 5 of 7
Empirical formula from masses (Higher)
Divide by Ar, divide by the smallest — the ratio of atoms falls out.
The empirical formula is the simplest whole-number ratio of atoms in a compound. From composition data the recipe is always the same three moves: divide each element’s mass (or percentage) by its Ar to get moles of atoms; divide every result by the smallest; if any ratio is not a whole number, multiply through to clear fractions (1.5 needs ×2, 1.33 ×3, 1.25 ×4). For a compound 40% calcium, 12% carbon and 48% oxygen: 40 ÷ 40 = 1, 12 ÷ 12 = 1, 48 ÷ 16 = 3 — ratio 1:1:3, empirical formula CaCO₃.
Notes · 6 of 7
Ionic equations (Higher)
Strip the equation to the particles that actually change.
When solutions react, many dissolved ions take no part in the change — they are spectator ions. The neutralisation of hydroxide by acid in every sodium-hydroxide-plus-hydrochloric-acid beaker is really just H⁺(aq) + OH⁻(aq) → H₂O(l): the Na⁺ and Cl⁻ ride along unchanged. Writing an ionic equation: write the full balanced equation with state symbols, split only aqueous ionic compounds into their ions, then cancel the spectators. For precipitation — AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq) — the ionic equation is Ag⁺(aq) + Cl⁻(aq) → AgCl(s), a white precipitate forming out of solution.
Notes · 7 of 7
Uncertainty, resolution and repeats
Every reading is honest only to half its smallest division.
A thermometer marked in 1 °C steps can justify a reading “to the nearest 1 °C”, but the true value may sit anywhere within ±0.5 °C: the uncertainty of a single reading is half the resolution of the instrument. Repeated measurements attack the problem differently: repeat a titration three times, discard the anomaly, and report the mean with the range — “24.35 cm³ (range 0.20 cm³)” — so the spread shows how much to trust the number. The tighter the range, the smaller the uncertainty of the mean.
Revise
Key terms
The words examiners expect you to use precisely.
- Balanced equation
- A symbol equation with equal numbers of every atom on both sides, adjusted with coefficients.
- Coefficient
- The large whole number in front of a formula in an equation, multiplying the whole formula.
- State symbol
- The label (s), (l), (g) or (aq) after a formula showing whether it is solid, liquid, gas or dissolved in water.
- Conservation of mass
- The law that total mass is unchanged in a reaction, because atoms are only rearranged.
- Non-enclosed system
- A reaction vessel open to the air, which may gain or lose gaseous reactants or products.
- Diatomic
- Existing as two-atom molecules — H₂, N₂, O₂, F₂, Cl₂, Br₂ and I₂.
Show 6 more key termsShow fewer key terms
- Relative atomic mass (Ar)
- The average mass of an element’s atoms compared with carbon-12, shown on the periodic table.
- Relative formula mass (Mr)
- The sum of all the Ar values in a compound’s formula.
- Empirical formula
- The simplest whole-number ratio of atoms of each element in a compound.
- Spectator ion
- An ion present in a solution reaction that takes no part in it and is cancelled from the ionic equation.
- Ionic equation
- An equation showing only the reacting particles, with spectators omitted and charge balanced.
- Uncertainty
- The interval a reading may really lie within — half the instrument’s resolution for a single measurement.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Balancing by changing subscripts, e.g. writing H₂O₂ to match oxygens.
Subscripts are the substance’s identity; H₂O₂ is hydrogen peroxide, not “fixed water”.
Instead: Balance only with coefficients in front of formulae.
Mistake: Forgetting the seven diatomic elements in equations.
Writing O instead of O₂ invents an atom arrangement oxygen never has.
Instead: H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂ — memorise the list.
Show 10 more mistakesShow fewer mistakes
Mistake: Saying mass is not conserved when a flask gets lighter.
The escaped gas is mass too — it just left the system.
Instead: Mass is conserved universally; open systems exchange gas with the surroundings.
Mistake: Expecting a burning metal’s ash to weigh less than the ribbon.
Burning adds oxygen from the air to the solid.
Instead: Magnesium gains mass on burning: the oxide includes the oxygen that combined.
Mistake: Adding Ar values without multiplying bracket contents, e.g. Ca(OH)₂ = 40 + 16 + 1.
The 2 outside the bracket applies to everything inside.
Instead: Ca(OH)₂ = 40 + 2 × 17 = 74.
Mistake: Reporting empirical formula straight from un-divided masses.
Masses of elements are never proportional to their atom counts.
Instead: Divide each mass by that element’s Ar first; ratios of moles, not grams, give the formula.
Mistake: Leaving a fractional ratio like 1:1.33 in an empirical formula.
Atoms come in whole numbers.
Instead: Multiply through to clear fractions: 1.33 ≈ 4/3, so ×3 gives 3:4.
Mistake: Including spectator ions in an ionic equation.
Spectators are unchanged on both sides — they are noise.
Instead: Split only aqueous ionic compounds, cancel identical ions from both sides, then check charge balance.
Mistake: Writing an ionic equation whose charges do not balance.
Charge, like atoms, must balance.
Instead: Zn + Cu²⁺ → Zn²⁺ + Cu balances atoms and charge (+2 both sides).
Mistake: Quoting a measurement beyond half its resolution.
A 1 °C thermometer cannot honestly support “21.37 °C”.
Instead: Uncertainty is ± half the resolution; a 1 °C thermometer reads to ±0.5 °C.
Mistake: Averaging every repeat including the wild outlier.
One bad titration drags the mean away from the truth.
Instead: Identify and discard anomalies, then average the consistent values and quote the range.
Mistake: Reading the coefficients as masses directly.
2Mg + O₂ → 2MgO does not mean 2 g of magnesium.
Instead: Coefficients give ratios in moles; mass conversions come next chapter.
Check yourself
Quick quiz
30 questions with instant explanations. About 5 minutes.
Question 1 of 3
- Question 1: current question
- Question 2: not answered
- Question 3: not answered
Check balancing
How many oxygen atoms are on the right-hand side of the balanced equation 4Al + 3O₂ → 2Al₂O₃?
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier and Chemistry-only questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 5 Practice Paper
30 marks · 40 min · 5 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 5: formulae and balancing, state symbols, conservation of mass in open and sealed systems, Mr, empirical formula (Higher), ionic equations (Higher), uncertainty.
Mark scheme
PROChapter 5 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
1 h 45 · 100 marks
Chapters 1–11: atoms, bonding, quantitative, chemical and energy changes
Paper 2
1 h 45 · 100 marks
Chapters 12–18: rates, organic, analysis, atmosphere, resources
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content; a periodic table is printed
Want a full paper? Try the Paper 1-style (Foundation), Paper 1-style (Higher), Paper 2-style (Foundation), Paper 2-style (Higher), Required practicals practice sets.
Questions
Frequently asked questions
Is there a shortcut for balancing equations?
Balance in order: metals, then non-metals, then hydrogen, then oxygen — and check by counting every element at the end. Fractions are allowed while you work (½O₂ is fine mid-balance), then double the whole equation to clear them.
Do I need to know Ar values by heart?
No — the periodic table in the exam lists them. You do need to use them fluently for Mr and, at Higher, empirical formula work.
What is the difference between empirical and molecular formula?
Empirical formula is the simplest whole-number ratio of atoms; molecular formula is the true count in one molecule and is always a whole-number multiple of the empirical one. Glucose CH₂O (empirical) and C₆H₁₂O₆ (molecular) is the classic pair.
When do I write an ionic equation?
Whenever ions in solution react — precipitation, neutralisation, displacement. Split only the (aq) ionic compounds, keep solids, liquids and gases whole, cancel spectators, and check that charge balances as well as atoms.
Does QuizQuip have any connection to the exam boards?
No. AQA, Pearson Edexcel and OCR are named only to identify the specifications this content supports. QuizQuip is not affiliated with, endorsed by, or connected to AQA, Pearson Edexcel or OCR, and no past-paper or specimen material is reproduced.
How much maths is in this chapter?
At least 10% of GCSE Chemistry marks are mathematical, and most land here and in the next chapter: balancing, Mr, empirical formula, ratios of moles and simple uncertainty statistics. The worked examples model every method step by step.
Up next
Chapter 6: The mole and reacting masses