Overview
What you’ll learn
- Explain why electrolysis needs molten or dissolved ionic compounds and label cathode and anode.
- Predict products for molten compounds and apply the competition rules for aqueous solutions.
- Describe the aluminium extraction cell and why cryolite is added.
- Write balanced half equations for each electrode (Higher) and link them to oxidation and reduction.
- Carry out and explain the aqueous electrolysis practical, including gas tests and the 2 : 1 volume ratio.
Specification checklist (AQA 8462 · Edexcel 1CH0 · OCR Gateway J248)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only, and statements badged Chemistry only are examined in separate (triple) Chemistry, not Combined Science. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 10.1Define electrolysis as splitting a molten or dissolved ionic compound using electricity, and explain why the compound must be molten or dissolved — the ions must be free to move.
- 10.2Identify the electrodes: the negative cathode attracts positive ions (cations), and the positive anode attracts negative ions (anions).
- 10.3Predict the products of electrolysis of a molten binary ionic compound: the metal forms at the cathode and the non-metal at the anode.
- 10.4Predict the products of aqueous electrolysis: at the cathode hydrogen forms unless the metal is less reactive than hydrogen (copper, silver); at the anode a halide forms halogen if present, otherwise oxygen from hydroxide ions.
- 10.5Describe the extraction of aluminium: molten aluminium oxide with cryolite added to lower the melting point, aluminium at the cathode, oxygen at the anode, and the carbon anodes burning away.
- 10.8Describe the required practical: electrolysis of aqueous solutions (sodium chloride, copper(II) sulfate with inert electrodes, dilute sulfuric acid) using inert electrodes, identifying the products at each electrode with the gas tests.
Higher — Higher tier only
- 10.6Write half equations for the reactions at each electrode (Higher), balancing atoms and charge, such as Al³⁺ + 3e⁻ → Al and 2Cl⁻ → Cl₂ + 2e⁻.
- 10.7Explain oxidation and reduction at each electrode in terms of electrons: reduction (gain) at the cathode, oxidation (loss) at the anode.
- 10.9Explain observations of the aqueous electrolysis practical: the 2 : 1 hydrogen-to-oxygen volume ratio from dilute sulfuric acid, chlorine’s bleaching effect from concentrated brine, and copper depositing on the cathode.
Key points
- 1Electrolysis splits molten or dissolved ionic compounds: the ions must be free to move, so solids will not conduct.
- 2Cathode (−) attracts cations (+): metals and hydrogen form there — reduction (gain of electrons).
- 3Anode (+) attracts anions (−): non-metals and halogens form there — oxidation (loss of electrons).
- 4Molten binary compounds: metal at the cathode, non-metal at the anode (molten lead bromide → lead + bromine).
- 5Aqueous rules: cathode — hydrogen unless the metal is less reactive than hydrogen (copper, silver); anode — halogen if a halide is present, otherwise oxygen from OH⁻.
- 6Aluminium cell: Al₂O₃ dissolved in molten cryolite (lowers melting point from 2072 °C to ~950 °C); Al at cathode, O₂ at anode, carbon anodes burn away as CO₂.
- 7Half equations (Higher): cathode gains electrons (Al³⁺ + 3e⁻ → Al); anode loses them (2Cl⁻ → Cl₂ + 2e⁻).
- 8Practical: brine → H₂ + Cl₂ (solution turns alkaline); CuSO₄ (inert electrodes) → Cu + O₂; dilute H₂SO₄ → H₂ and O₂ in a 2 : 1 ratio.
Notes · 1 of 5
What electrolysis is, and why state matters
A solid ionic crystal cannot conduct — free the ions first, then current does the chemistry.
Electrolysis means “splitting with electricity”: a direct current passed through an electrolyte decomposes it at two electrodes. Only ionic compounds can be electrolysed, and only when their ions are free to move — molten, or dissolved in water. A solid crystal locks every ion in place, so it will not conduct; a melted or dissolved one swims with mobile charge carriers. The cathode is the negative electrode and pulls positive ions (cations) onto itself; the anode is positive and pulls negative ions (anions). At the cathode, ions gain electrons (reduction); at the anode they lose electrons (oxidation).
| Property | Cathode | Anode |
|---|---|---|
| Charge | Negative | Positive |
| Attracts | Cations (+) | Anions (−) |
| Product | Metals; hydrogen from water | Non-metals; halogens; oxygen |
| Process | Reduction (gain e⁻) | Oxidation (loss e⁻) |
Notes · 2 of 5
Aqueous electrolysis: the competition rules
Water enters contestants at both electrodes — the series and the halides decide who wins.
Dissolve an ionic compound and water supplies its own ions: H⁺ (with the cation at the cathode) and OH⁻ (with the anion at the anode). Two rules settle the contests. At the cathode, hydrogen gas forms unless the metal is less reactive than hydrogen — copper and silver are lazy enough to deposit as metal instead. At the anode, if halide ions (Cl⁻, Br⁻, I⁻) are present in reasonable concentration, the halogen forms; if not, oxygen is released from the hydroxide ions.
| Solution | Cathode | Anode | Solution change |
|---|---|---|---|
| Concentrated NaCl (brine) | Hydrogen | Chlorine (pale green) | Turns alkaline (NaOH left) |
| Dilute NaCl | Hydrogen | Oxygen | Slowly less salty |
| CuSO₄ | Copper coating | Oxygen | Blue fades as Cu²⁺ used |
| Dilute H₂SO₄ | Hydrogen | Oxygen | H₂ : O₂ volume = 2 : 1 |
Notes · 3 of 5
Half equations (Higher)
One line per electrode, balanced for atoms and charge.
A half equation shows the electrons explicitly. Cathode (reduction): electrons on the left — Al³⁺ + 3e⁻ → Al; 2H⁺ + 2e⁻ → H₂; Cu²⁺ + 2e⁻ → Cu. Anode (oxidation): electrons on the right — 2Cl⁻ → Cl₂ + 2e⁻; 2O²⁻ → O₂ + 4e⁻; 4OH⁻ → O₂ + 2H₂O + 4e⁻ (aqueous oxygen). Balance the atoms first, then the charge — every half equation must balance both.
Notes · 4 of 5
The aluminium cell
Molten cryolite melts the bill: how the world gets aluminium without heating Al₂O₃ to 2072 °C.
Aluminium oxide melts far too high (2072 °C) to electrolyse economically as a pure melt. The cell therefore dissolves the alumina in molten cryolite, a less common aluminium mineral, cutting the working temperature to about 950 °C. Alumina is fed in continuously; Al³⁺ reduces at the carbon-lined cathode (molten aluminium taps out at the bottom) and O²⁻ oxidises at carbon anodes. The oxygen attacks the hot carbon: C + O₂ → CO₂, so the anodes burn away and must be replaced regularly — part of the process’s cost, alongside the enormous electricity demand that puts smelters next to power stations.
Notes · 5 of 5
Required practical: aqueous electrolysis
Inert electrodes, gas tests, and the 2 : 1 surprise of water.
- 1Set-up
Beaker of solution, two inert electrodes (carbon/graphite or platinum) connected to a low-voltage DC supply.
- 2Brine (concentrated NaCl)
Cathode: hydrogen (squeaky pop). Anode: chlorine — pale green, bleaches damp litmus paper. The solution goes alkaline: NaOH forms. Half equations: 2H⁺ + 2e⁻ → H₂ and 2Cl⁻ → Cl₂ + 2e⁻.
- 3Copper sulfate (inert electrodes)
Cathode: pink-brown copper coating grows (Cu²⁺ + 2e⁻ → Cu). Anode: oxygen bubbles (4OH⁻ → O₂ + 2H₂O + 4e⁻). The blue colour fades as Cu²⁺ is used up.
- 4Dilute sulfuric acid
Hydrogen at the cathode, oxygen at the anode — collected and tested. The volumes come out 2 : 1 H₂ : O₂, because water (H₂O) contains exactly twice as many hydrogen as oxygen atoms.
Variables to control: voltage, electrode separation, concentration and volume of solution. Hazards: chlorine is toxic (ventilate, small quantities); hydrogen is flammable (no flames). Evaluation points: carbon electrodes can crumble and discolour products; platinum is better but pricey.
Revise
Key terms
The words examiners expect you to use precisely.
- Electrolysis
- Decomposing a molten or dissolved ionic compound by passing a direct current through it.
- Electrolyte
- The molten or dissolved ionic compound whose mobile ions carry the current.
- Electrode
- A conductor dipped into the electrolyte; inert electrodes like carbon do not react themselves.
- Cathode
- The negative electrode, attracting cations; reduction (electron gain) happens here.
- Anode
- The positive electrode, attracting anions; oxidation (electron loss) happens here.
- Cation
- A positive ion, drawn to the cathode — metals and hydrogen.
Show 6 more key termsShow fewer key terms
- Anion
- A negative ion, drawn to the anode — non-metals, halides, hydroxide.
- Half equation
- An electrode equation showing electrons explicitly, balanced for atoms and charge.
- Cryolite
- The molten solvent that dissolves aluminium oxide, lowering the operating temperature of the cell.
- Brine
- Concentrated sodium chloride solution; its electrolysis makes hydrogen, chlorine and sodium hydroxide.
- Inert electrode
- An electrode that conducts but does not react, so it does not supply ions.
- Disproportionation
- When one substance is both oxidised and reduced — chlorine in water, for example (extension).
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Electrolysing solid salt “because it contains ions”.
Fixed ions cannot move to the electrodes.
Instead: The compound must be molten or dissolved; then the ions migrate.
Mistake: Mixing up cathode and anode charges.
Positive ions flee positive electrodes.
Instead: Cathode = negative = cations; anode = positive = anions. (PANIC: Positive Anode, Negative Is Cathode.)
Show 10 more mistakesShow fewer mistakes
Mistake: Predicting magnesium metal from aqueous MgCl₂ electrolysis.
Magnesium is far more reactive than hydrogen — water wins at the cathode.
Instead: Hydrogen forms unless the metal is less reactive than hydrogen (Cu, Ag).
Mistake: Predicting oxygen at the anode of concentrated brine.
Concentrated halide ions out-compete hydroxide.
Instead: Halide present → halogen. Only halide-free solutions give oxygen.
Mistake: Putting electrons on the wrong side of a half equation.
Cathode reactions consume electrons; anode reactions release them.
Instead: Reduction: electrons left (Cu²⁺ + 2e⁻ → Cu). Oxidation: electrons right (2Cl⁻ → Cl₂ + 2e⁻).
Mistake: Writing an unbalanced half equation like Al³⁺ + e⁻ → Al.
Charge does not balance: +3 left, 0 right.
Instead: Al³⁺ + 3e⁻ → Al — three electrons for the 3+ charge.
Mistake: Forgetting state labels and water in the OH⁻ half equation.
4OH⁻ → O₂ + 4e⁻ has hydrogens that vanish.
Instead: 4OH⁻ → O₂ + 2H₂O + 4e⁻ — atoms and charge both balance.
Mistake: Saying cryolite “lowers the melting point of aluminium oxide”.
Cryolite dissolves the alumina — the mixture’s working temperature drops; the alumina itself does not melt.
Instead: Alumina dissolves in molten cryolite so the cell runs near 950 °C instead of 2072 °C.
Mistake: Missing the burning anodes in the aluminium cell.
The oxygen product attacks the hot carbon.
Instead: Carbon anodes burn away as CO₂ and need regular replacement — a real cost of the process.
Mistake: Explaining the 2 : 1 gas ratio as “hydrogen is lighter”.
Volumes of gas depend on particle counts, not masses.
Instead: Every 2 water molecules yield 2 H₂ and 1 O₂ — twice as many hydrogen molecules form.
Mistake: Using reactive metal electrodes in the practical and expecting the same products.
Reactive electrodes dissolve themselves instead of letting the solution react.
Instead: The practical specifies inert (carbon or platinum) electrodes.
Mistake: Saying the blue copper sulfate solution stays blue throughout.
Cu²⁺ is consumed at the cathode.
Instead: The blue fades as Cu²⁺ ions are removed and copper metal plates out.
Check yourself
Quick quiz
30 questions with instant explanations. About 5 minutes.
Question 1 of 3
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Define electrolysis
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier and Chemistry-only questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 10 Practice Paper
30 marks · 40 min · 5 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 10: molten and aqueous electrolysis, product prediction rules, the aluminium cell, half equations (Higher) and the aqueous electrolysis required practical.
Mark scheme
PROChapter 10 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
1 h 45 · 100 marks
Chapters 1–11: atoms, bonding, quantitative, chemical and energy changes
Paper 2
1 h 45 · 100 marks
Chapters 12–18: rates, organic, analysis, atmosphere, resources
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content; a periodic table is printed
Want a full paper? Try the Paper 1-style (Foundation), Paper 1-style (Higher), Paper 2-style (Foundation), Paper 2-style (Higher), Required practicals practice sets.
Questions
Frequently asked questions
How do I remember which electrode is which?
PANIC: Positive Anode, Negative Is Cathode. Then remember opposites attract — cations to the cathode, anions to the anode.
What are the two aqueous rules, in one breath?
Cathode: hydrogen unless the metal is less reactive than hydrogen. Anode: halogen if a halide is there, otherwise oxygen. Two rules cover every aqueous prediction.
Do half equations need balancing?
Yes — atoms and charge, both. A half equation with unbalanced charge (Al³⁺ + e⁻ → Al) loses the mark even if the atoms are right.
Is brine electrolysis still industrial chemistry?
Very much so — hydrogen, chlorine and sodium hydroxide are all major products. That is why the practical matters beyond the exam.
Does QuizQuip have any connection to the exam boards?
No. AQA, Pearson Edexcel and OCR are named only to identify the specifications this content supports. QuizQuip is not affiliated with, endorsed by, or connected to AQA, Pearson Edexcel or OCR, and no past-paper or specimen material is reproduced.
How does this connect to metal extraction?
Chapter 9 ended with metals above carbon needing electrolysis — aluminium being the headline case, covered fully here. Same physics, industrial scale.
Up next
Chapter 11: Energy changes