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Chapter 9Theme 3 · Thermal PhysicsG2 / G3

Sec 3 Physics Thermal Properties of Matter notes

How much energy does it take to warm soup, melt ice, or boil a kettle dry? This chapter prices each job: specific heat capacity for temperature changes, specific latent heat for changes of state — and the curious plateaux where a substance changes state at constant temperature while energy pours in.

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Overview

What you’ll learn

  • Describe internal energy as the total kinetic energy of the particles’ random motion plus the total potential energy between the particles.
  • Define heat capacity and specific heat capacity.
  • Recall and apply energy transferred by heating = mass × specific heat capacity × temperature change (E = mcΔθ).
  • Describe melting/solidification and boiling/condensation as transfers of energy without a temperature change.
  • Explain the difference between boiling and evaporation.
  • Define latent heat and specific latent heat.
  • Recall and apply energy transferred for a change of state = mass × specific latent heat (E = ml).
  • Explain latent heat in terms of the behaviour of particles.
  • Sketch and interpret a cooling curve.

In 30 seconds

  1. 1Internal energy = the particles’ total kinetic energy (random motion) + total potential energy (between particles).
  2. 2Specific heat capacity c = energy to raise 1 kg by 1 °C; E = mcΔθ. Water’s c = 4200 J/(kg·°C) is huge — it is the coolant of choice.
  3. 3Melting and boiling happen at constant temperature: the energy goes into particle separation, not speed.
  4. 4Boiling happens throughout the liquid at one fixed temperature; evaporation happens only at the surface, at any temperature — and cools what remains.
  5. 5Specific latent heat l = energy to change the state of 1 kg with no temperature change; E = ml.
  6. 6Latent heat of vaporisation ≫ latent heat of fusion: boiling separates particles almost completely.
  7. 7A cooling curve falls steeply, plateaus at the freezing point (solid + liquid coexisting), then falls again as the solid cools.

Notes · 1 of 5

Internal energy

Two accounts: kinetic energy of motion and potential energy of separation.

The internal energy of a body is the grand total of its particles’ energies: the kinetic energy of their random motion (bigger when hotter) plus the potential energy stored between them as they attract and repel (bigger when they are pulled further apart). Heating raises internal energy — sometimes in the kinetic account (temperature rises), sometimes in the potential account (the substance changes state), often in both.

Keeping the two accounts separate explains everything in this chapter. A thermometer reads only the kinetic account. Energy that flows in while the temperature stays put (melting, boiling) must be going into the potential account — stretching the particles apart against their attractions. Cooling is the reverse bookkeeping.

Notes · 2 of 5

Heat capacity and specific heat capacity

How expensive is one more degree? Depends how much stuff and what it is.

The heat capacity of a body is the energy needed to raise the whole body by 1 °C. The specific heat capacity (c) normalises it: the energy needed to raise 1 kg of the substance by 1 °C, in J/(kg·°C). Rearranged into the working formula: E = mcΔθ — energy equals mass times specific heat capacity times the temperature change.

Water’s specific heat capacity, 4200 J/(kg·°C), is enormous for an everyday liquid: a kettle must supply 4200 J just to warm one kilogram by one degree. That is a feature, not a bug — it is why water cools engines, carries heat around central-heating systems, and keeps Singapore’s climate mild near the sea: a huge energy change buys only a small temperature change.

Notes · 3 of 5

Melting, boiling and evaporation

Changes of state hold the temperature still — and evaporation cools.

A pure substance melts and boils at fixed temperatures (its melting and boiling points). While ice melts at 0 °C, a thermometer in the ice-water mixture holds steady even though energy flows in: the energy is potential-account spending, pulling particles apart. The same hold applies at the boiling point: bubbling water stays at 100 °C until the last of it has boiled away.

Boiling and evaporation both turn liquid into vapour, but they are different processes. Boiling occurs throughout the liquid (bubbles form at the bottom), only at the boiling point, and needs an external energy supply. Evaporation happens only at the surface, at any temperature below the boiling point, and — crucially — takes its energy from the liquid itself, which is why evaporation cools what remains: sweating is the body’s own air-conditioning.

Boiling versus evaporation
FeatureBoilingEvaporation
Wherethroughout the liquid (bubbles)only at the surface
Temperatureonly at the boiling pointany temperature
Energy sourcesupplied from outside (flame, heater)taken from the liquid itself
Effect on the liquidtemperature stays constantthe remaining liquid cools
Bubblesyes — vapour within the liquidnone

Notes · 4 of 5

Latent heat and specific latent heat

The hidden price of changing state — hidden because the thermometer cannot see it.

Latent heat is the energy absorbed or released during a change of state with no temperature change — "latent" because it hides from the thermometer. The specific latent heat (l) normalises it to 1 kg: E = ml. Two flavours matter: the specific latent heat of fusion (melting/solidifying; for water ≈ 3.34 × 10⁵ J/kg) and of vaporisation (boiling/condensing; for water ≈ 2.26 × 10⁶ J/kg). Remember: values like these are given in the question — the exam carries no data booklet, but it always supplies what it wants you to use.

In particle terms: melting must pull particles partly free of the lattice (potential energy up, kinetic account unchanged), and boiling must separate them almost completely — which is why vaporisation’s latent heat is several times fusion’s. Freezing and condensing run the film backwards and release exactly the same energies: steam scalds far worse than boiling water because each condensing kilogram hands over 2.26 × 10⁶ J on contact.

Notes · 5 of 5

Cooling curves

Read the plateaux: they are the change of state, drawn in flat ink.

A cooling curve plots temperature against time as a hot substance cools. The signature shape: a steep fall while the liquid cools; a flat plateau at the freezing point while the liquid solidifies (the released latent heat exactly offsets the energy lost to the room); then a further fall as the solid cools. The plateau is the thermometer’s blind spot for latent heat — the freezing point can be read off it to the degree.

Heating runs the same graph backwards: a rise, a flat melting plateau (solid + liquid coexisting), another rise through the liquid stage, then a hold at the boiling point. Reading questions hand you such a curve and ask: What is the melting point? Where is the substance partly solid and partly liquid? Why is one section steeper? — the answers live in the slopes and plateaux.

Revise

Key terms

The words examiners expect you to use precisely.

internal energy
The total kinetic energy of the particles’ random motion plus the total potential energy between the particles.
heat capacity
The energy needed to raise the temperature of a whole body by 1 °C (J/°C).
specific heat capacity
The energy needed to raise 1 kg of a substance by 1 °C; E = mcΔθ, in J/(kg·°C).
melting point
The fixed temperature at which a pure substance melts (and solidifies).
boiling point
The fixed temperature at which a pure substance boils throughout the liquid.
evaporation
Slow vaporisation at the surface of a liquid at any temperature, cooling the liquid that remains.
Show 6 more key terms
boiling
Rapid vaporisation throughout the liquid at the boiling point, with bubbles of vapour forming.
latent heat
The energy absorbed or released during a change of state at constant temperature.
specific latent heat
The energy to change the state of 1 kg of a substance with no temperature change; E = ml, in J/kg.
specific latent heat of fusion
The value for melting or solidifying (water: ≈3.34 × 10⁵ J/kg).
specific latent heat of vaporisation
The value for boiling or condensing (water: ≈2.26 × 10⁶ J/kg).
cooling curve
A graph of temperature against time while a substance cools, whose plateau marks the freezing point.

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Expecting the temperature to rise while a substance melts or boils.

    During a change of state the energy goes into particle separation, not speed.

    Instead: Plateau: energy → potential account; temperature moves only after the state change finishes.

  • Mistake: Confusing heat capacity with specific heat capacity.

    One belongs to the whole body, the other to 1 kg of the material.

    Instead: "Specific" = per kilogram; use E = mcΔθ with c in J/(kg·°C).

Show 10 more mistakes
  • Mistake: Forgetting to convert grams to kilograms in E = mcΔθ or E = ml.

    A 200 g sample entered as "200" inflates the answer a thousandfold.

    Instead: Mass in kg before anything else: 200 g = 0.200 kg.

  • Mistake: Using Δθ in Celsius with a latent-heat formula or vice versa.

    E = mcΔθ needs a temperature difference; E = ml needs none — mixing them doubles the error.

    Instead: Ask first: is the temperature changing (c) or is the state changing (l)?

  • Mistake: Thinking evaporation needs the liquid to reach 100 °C.

    Evaporation happens at any temperature, from puddles to washing lines.

    Instead: Boiling needs the boiling point; evaporation never stops, it just slows.

  • Mistake: Saying evaporation does not cool the liquid.

    The fastest molecules leave, lowering the average kinetic energy of those behind.

    Instead: Evaporation is the cooling mechanism behind sweat and dewy cold water bottles.

  • Mistake: Believing steam at 100 °C and boiling water at 100 °C deliver the same scald.

    Condensing steam releases its full latent heat first — several times more energy per kilogram.

    Instead: Steam burns are worse because E = ml (vaporisation) is added to the cooling water’s bill.

  • Mistake: Reading a cooling curve’s plateau as "the substance is losing no energy".

    Energy leaves steadily; the released latent heat cancels the loss, holding the temperature.

    Instead: Plateau = change of state, with solid and liquid coexisting.

  • Mistake: Naming the freezing point from the steepest part of the curve.

    The freezing point is the flat plateau, not the slope.

    Instead: Plateaux mark state changes; slopes mark single-phase cooling or warming.

  • Mistake: Quoting latent heat values "remembered" instead of using the values given in the question.

    The exam supplies its own data; recalled numbers may differ and cost the accuracy mark.

    Instead: Read the stem, use its constants, and state them in the working.

  • Mistake: Forgetting to add both stages (melt, then warm) in ice-to-water problems.

    Ice at 0 °C needs latent heat first and sensible heat second; either half alone under-counts.

    Instead: Split the journey into state-change and temperature-change stages and add them.

  • Mistake: Saying the internal energy of a body is only its kinetic part.

    Internal energy = kinetic (motion) + potential (separation) accounts together.

    Instead: Temperature tracks the kinetic account only; the potential account moves during state changes.

Check yourself

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Question 1 of 3

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Describe internal energy as kinetic plus potential energy of the particles.

Internal energy is the sum of

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Chapter 9 Practice Paper

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5 multiple-choice questions and structured questions with answer lines. Internal energy, specific heat capacity, melting and boiling, specific latent heat, cooling curves.

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Chapter 9 Practice Paper — mark scheme

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Model answers with a mark for each creditworthy point — for marking at home or in class.

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Where this chapter is tested

Each school sets its own scope — check your assessment outline.

Questions

Frequently asked questions

What does Sec 3 Physics Chapter 9 cover?

It covers the thermal properties topic of O-Level Physics 6091: internal energy (kinetic + potential particle energy), heat and specific heat capacity with E = mcΔθ, melting and boiling at constant temperature, boiling versus evaporation, specific latent heat with E = ml, and sketching and reading cooling curves.

Do I need to memorise the specific heat capacity of water?

Yes — c(water) = 4200 J/(kg·°C) is assumed knowledge in most schemes and appears constantly in questions. Latent heat values, by contrast, are normally supplied in the question stem, and you should use the given numbers even if they differ.

Why does my E = mcΔθ answer not match the mark scheme?

Check three usual slips: mass in kilograms (not grams), the temperature CHANGE (not the final temperature), and the right formula for the job (mcΔθ for warming, ml for a change of state — never both at once).

Are these questions from past O-Level papers?

No. All notes, quizzes and papers on this page are original QuizQuip material written against the published syllabus, in Paper 1 and Paper 2 style. QuizQuip is not affiliated with MOE or SEAB and does not host school or examination papers.

When is this chapter usually tested in school?

Thermal properties close the Sec 3 thermal block in Term 4, so they appear in the end-of-year examination — and specific heat capacity and latent heat calculations are staples of the practical paper too. Scope varies by school; check your school’s assessment outline.