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Chapter 5Theme 2 · Newtonian MechanicsG2 / G3

Sec 3 Physics Pressure notes

The same force can sink into snow or glide over it — the difference is pressure. This chapter defines pressure as force spread over area, follows it into liquids where it grows with depth and transmits equally through hydraulics, then measures the atmosphere itself with columns of liquid and a manometer.

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Overview

What you’ll learn

  • Define pressure in terms of force and area, and apply pressure = force ÷ area.
  • Describe and explain the transmission of pressure in hydraulic systems, including the hydraulic press.
  • Recall and apply density = mass ÷ volume.
  • Recall and apply the pressure due to a liquid column: p = hρg.
  • Describe how the height of a liquid column may be used to measure atmospheric pressure.
  • Describe the use of a manometer to measure pressure differences.

In 30 seconds

  1. 1Pressure = force ÷ area, in pascals: 1 Pa = 1 N/m².
  2. 2Same force, smaller area → bigger pressure: the physics of snow shoes, stilettos and camel feet.
  3. 3Pressure applied to an enclosed liquid transmits equally in every direction — the hydraulic press turns a small force on a small piston into a large force on a large one.
  4. 4Hydraulics multiply force, never energy: the small piston moves much further than the large one.
  5. 5Density = mass ÷ volume; water is 1000 kg/m³ = 1 g/cm³.
  6. 6Liquid pressure grows with depth: p = hρg, and it acts equally in all directions at a point.
  7. 7A liquid column barometer balances the atmosphere against a column of liquid; denser liquids stand shorter.
  8. 8A manometer measures a pressure difference as the height difference between the two arms of a U-tube: Δp = hρg.

Notes · 1 of 5

Pressure, force and area

Spread the same push over less area and it bites harder.

Pressure is the force acting perpendicularly per unit area: pressure = force ÷ area, with the unit pascal (1 Pa = 1 N/m²). It explains why a stiletto heel dents a wooden floor a flat shoe does not: the same weight squeezes through a heel a hundred times smaller in area, so the pressure is a hundred times bigger.

Watch the areas: questions quote cm² as often as m², and 1 m² = 10 000 cm². Converting sloppily by a factor of 100 or 10 000 is the single biggest mark-loser in this topic. The force must also act perpendicularly to the surface — a foot pressing squarely, not a leaning ladder.

Notes · 2 of 5

Density

How tightly the matter is packed — the bridge from mass to liquid pressure.

Density is the mass per unit volume: ρ = m ÷ V. Water has ρ = 1000 kg/m³, which equals 1 g/cm³ — a useful bridge because questions mix the two unit families freely. Densities decide floating (less dense floats on more dense) and enter the liquid-pressure formula directly.

Converting between the unit families: to turn g/cm³ into kg/m³ multiply by 1000 (there are a million cm³ in a m³ but a thousand grams in a kilogram). So 2.7 g/cm³ = 2700 kg/m³ (aluminium), 0.92 g/cm³ = 920 kg/m³ (oil, which floats on water).

Notes · 3 of 5

Pressure in liquids: p = hρg

Deeper means denser-handed: pressure grows with depth, not with width.

A liquid column of height h and density ρ presses down with the weight of the liquid above: pressure p = hρg. The shape and width of the container are irrelevant — a deep narrow tube and a wide lake give the same pressure at the same depth. Liquid pressure also acts equally in all directions at a point, which is why a dam wall is thicker at the bottom: the water there pushes hardest.

Notes · 4 of 5

Hydraulic systems

Liquids pass pressure on faithfully — and that passes forces up.

Liquids are nearly incompressible, so pushing a piston raises the pressure everywhere in the connected liquid by the same amount (pressure transmits equally in all directions). A second piston of larger area then feels a larger force: F = p × A. This is the hydraulic press, the car jack, the dentist’s chair and the excavator arm all at once.

The force-multiplying ratio equals the area ratio: F₂ ÷ F₁ = A₂ ÷ A₁. But the small piston must travel proportionally further — volume pushed in at one end equals volume delivered at the other — so energy is conserved: small force × big distance = big force × small distance.

Real systems add a note worth quoting for full marks: the liquid must have no air bubbles (air compresses and makes the control spongy) and the pistons must not leak — the equal-transmission principle assumes an enclosed, continuous liquid.

Notes · 5 of 5

Measuring pressure: columns and U-tubes

The atmosphere holds up a column of liquid; a U-tube compares two pressures.

The atmosphere presses on everything at about 100 kPa — the weight of a kilometres-deep ocean of air. A liquid-column barometer measures it: the atmosphere balances a column of liquid, and at equilibrium atmospheric pressure = hρg for the column. With water (ρ = 1000 kg/m³) the column would stand 100 000 ÷ (1000 × 10) = 10 m tall — hopeless for a lab bench. Mercury, 13.6 times denser, stands about 0.76 m, which is why old barometers used it and why pressure is still quoted in "mm Hg".

A manometer is a U-tube of liquid comparing two pressures. With one arm open to the air, the height difference h between the arms gives the excess of the gas pressure over atmospheric: Δp = hρg. If the gas pushes its arm down, the gas is above atmospheric; if it lets its arm rise, the gas is below (a partial vacuum). Denser liquids read shorter columns for the same pressure — the measuring liquid is chosen for the range needed.

Revise

Key terms

The words examiners expect you to use precisely.

pressure
The force acting perpendicularly per unit area, p = F/A, measured in pascals (1 Pa = 1 N/m²).
pascal (Pa)
The SI unit of pressure: one newton of force spread over one square metre.
density
Mass per unit volume, ρ = m/V; water is 1000 kg/m³ (1 g/cm³).
hydraulic system
A system using an enclosed liquid to transmit pressure, multiplying force from a small piston to a large one.
Pascal’s principle
Pressure applied to an enclosed liquid is transmitted equally in all directions (the basis of hydraulics).
liquid-column pressure
The pressure at the foot of a liquid column of height h and density ρ: p = hρg.
Show 4 more key terms
atmospheric pressure
The pressure exerted by the weight of the air, about 100 kPa at sea level.
barometer
An instrument measuring atmospheric pressure by balancing it against the height of a liquid column.
manometer
A U-tube of liquid used to measure a pressure difference from the height difference between its arms.
excess (gauge) pressure
A pressure measured relative to atmospheric pressure, as read by a manometer.

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Quoting pressure in newtons or forgetting to divide by the area.

    Pressure is a force-per-area quantity, not a force; skipping the division reports the force itself.

    Instead: p = F ÷ A every time, with the answer in Pa (N/m²).

  • Mistake: Forgetting 1 m² = 10 000 cm².

    A factor of 100 slip inflates or deflates every pressure by two orders of magnitude.

    Instead: Convert areas to m² before dividing: 25 cm² = 25 × 10⁻⁴ m².

Show 11 more mistakes
  • Mistake: Halving the area and expecting the pressure to halve.

    Area sits under the division line: halving the area doubles the pressure.

    Instead: Pressure is inversely proportional to area at fixed force.

  • Mistake: Using slanted or total surface area instead of the perpendicular contact area.

    Only the force component perpendicular to the surface, over the contact area, sets the pressure on it.

    Instead: Take the force pressing squarely into the surface and divide by the area of contact.

  • Mistake: Saying hydraulics multiply energy.

    Force is multiplied but distance shrinks by the same ratio; work in equals work out.

    Instead: The small piston travels much further — energy is conserved, only force is traded up.

  • Mistake: Expecting the wide piston to move further than the narrow one.

    The large piston moves a shorter distance: the pushed-in volume is shared over a bigger area.

    Instead: Distance ratio is the inverse of the area ratio.

  • Mistake: Using p = hρg with h measured from the container bottom.

    Liquid pressure depends on depth below the free surface, not height above the base.

    Instead: h is the vertical distance down from the liquid surface to the point.

  • Mistake: Adding the container’s width or shape into liquid pressure.

    p = hρg has no area or shape term; a narrow tube and a lake agree at the same depth.

    Instead: Only depth, density and g enter liquid pressure.

  • Mistake: Forgetting atmospheric pressure when a question asks for total (absolute) pressure.

    hρg gives only the liquid’s contribution; a diver feels the atmosphere on top of it.

    Instead: Total pressure = atmospheric + hρg, unless the question says "pressure due to the liquid".

  • Mistake: Reading a manometer as giving absolute pressure directly.

    The height difference measures the difference between the two arms’ pressures.

    Instead: Excess pressure = hρg; add atmospheric pressure for the absolute value.

  • Mistake: Ignoring the density unit conversion in p = hρg.

    Using 1 g/cm³ directly in SI gives pressures out by a factor of 1000.

    Instead: Work in kg/m³ (multiply g/cm³ by 1000) with h in metres and g = 10 N/kg.

  • Mistake: Saying suction pulls the drink up a straw.

    Suction only lowers the pressure in the mouth; the atmosphere does the pushing.

    Instead: Atmospheric pressure on the liquid surface pushes the liquid up the straw — hence the ~1 m limit.

  • Mistake: Choosing a denser manometer liquid and expecting a taller column.

    h = Δp ÷ (ρg): denser liquids stand shorter for the same pressure difference.

    Instead: Density and column height are inversely related at fixed pressure.

Check yourself

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Define pressure in terms of force and area.

One pascal equals

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Chapter 5 Practice Paper

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5 multiple-choice questions and structured questions with answer lines. Pressure = force/area, hydraulic systems, density, liquid-column pressure, barometers and manometers.

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Chapter 5 Practice Paper — mark scheme

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Model answers with a mark for each creditworthy point — for marking at home or in class.

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Where this chapter is tested

Each school sets its own scope — check your assessment outline.

Questions

Frequently asked questions

What does Sec 3 Physics Chapter 5 cover?

It covers the pressure topic of O-Level Physics 6091: pressure = force ÷ area with pascals, density = mass ÷ volume, liquid-column pressure p = hρg, the transmission of pressure in hydraulic systems and the hydraulic press, liquid-column barometers for atmospheric pressure, and manometers for pressure differences.

Why does the course use g = 10 N/kg?

The syllabus takes the gravitational field strength near the Earth as approximately 10 N/kg (identical to the 10 m/s² of free fall). Every pressure calculation here uses that value unless a question states otherwise — declare it once in your working.

Why does my manometer answer not match the mark scheme?

Two usual causes: forgetting to convert cm to m (0.16 m, not 16 m) or the density to kg/m³ (oil at 800–900, mercury at 13 600), or reading the height difference as absolute pressure. The manometer gives the difference; add atmospheric pressure for the absolute value.

Are these questions from past O-Level papers?

No. All notes, quizzes and papers on this page are original QuizQuip material written against the published syllabus, in Paper 1 and Paper 2 style. QuizQuip is not affiliated with MOE or SEAB and does not host school or examination papers.

When is this chapter usually tested in school?

Pressure usually lands mid-Sec 3 (Term 2 or 3), so it appears in Weighted Assessment 2 or a Term 3 test and the end-of-year examination; hydraulic and manometer questions also appear in practical-style papers. Scope varies by school — check your school’s assessment outline.

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