Overview
What you’ll learn
- Apply the index laws to multiply, divide and raise powers, and evaluate the zero index.
- Rewrite negative indices as reciprocals and fractional indices as roots, then evaluate them (Higher).
- Simplify surds by extracting square factors, combine like surds, and rationalise denominators including the (a + √b) form (Higher).
- Give exact answers with fractions, surds and multiples of π instead of rounded decimals.
- Convert between ordinary numbers and standard form, and multiply and divide in standard form.
Specification checklist (AQA 8300 · Edexcel 1MA1 · OCR J560)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 3.1Use the laws of indices with positive integer powers: multiply powers with the same base by adding indices, divide by subtracting, raise a power to a power by multiplying, and use the zero index a⁰ = 1.
- 3.4Calculate exactly with fractions, surds and multiples of π, giving exact answers in place of rounded decimals where a question demands them.
- 3.5Calculate with and interpret standard form A × 10ⁿ, where 1 ≤ A < 10 and n is an integer: convert in both directions, and multiply and divide numbers in standard form.
Higher — Higher tier only
- 3.2Calculate with integer and fractional indices: use negative indices as reciprocals and fractional indices as roots, including a^(1/n) and a^(m/n). (Higher)
- 3.3Simplify surd expressions involving squares (such as √12 = √4 × √3 = 2√3), add and multiply simple surds, and rationalise denominators. (Higher)
Key points
- 1Same base? Add indices to multiply: 2³ × 2⁴ = 2⁷. Subtract to divide: 5⁶ ÷ 5⁴ = 5². Multiply for a power of a power: (3²)³ = 3⁶.
- 2Anything to the power zero is 1 (the base is not zero): 7⁰ = 1, (5x)⁰ = 1.
- 3Negative index = reciprocal: 3⁻² = 1⁄3² = 1⁄9 (Higher).
- 4Fractional index = root: a^(1/2) = √a, a^(1/3) = ∛a, and 8^(2/3) = (∛8)² = 4 (Higher).
- 5Pull out square factors to simplify surds: √12 = √4 × √3 = 2√3; only like surds add: √27 + √12 = 5√3 (Higher).
- 6Rationalise by multiplying top and bottom by the surd (or its conjugate): 1⁄√3 = √3⁄3, and 1⁄(3 − √2) multiplies by (3 + √2)⁄(3 + √2) (Higher).
- 7Standard form: A × 10ⁿ with 1 ≤ A < 10. Big numbers → positive n; small numbers → negative n.
- 8In standard-form products, multiply the A values and add the indices: (3 × 10⁵) × (4 × 10⁻²) = 1.2 × 10⁴ after re-normalising.
Notes · 1 of 5
The index laws
Add, subtract and multiply indices — never multiply them across terms.
An index (power) counts repeated multiplication. The three core laws all follow from that counting: 2³ × 2⁴ = (2×2×2) × (2×2×2×2) = 2⁷, so multiplying powers with the same base adds indices. Dividing cancels factors, so 5⁶ ÷ 5⁴ = 5². Raising a power to a power repeats the whole block, so (3²)³ = 3⁶. The laws need the same base: 2³ × 3² cannot merge, and neither can 2³ + 2⁴ (index laws are about multiplication and division only).
The zero index completes the subtract rule: 7³ ÷ 7³ = 7⁰, but also equals 1, so 7⁰ = 1 — anything non-zero to the power zero is 1. Watch the brackets: −2² means −(2²) = −4, while (−2)² = 4. And a common trap: (2x)³ = 2³x³ = 8x³, not 2x³.
Notes · 2 of 5
Negative and fractional indices
A negative index flips; a fractional index takes a root. (Higher)
The subtract rule forces negative indices to mean reciprocals: 5² ÷ 5⁴ = 5⁻², but working it out gives 1⁄25, so 5⁻² = 1⁄5². In general a⁻ⁿ = 1⁄aⁿ, and the flip works both ways: 1⁄2⁻³ = 2³ = 8. Fractional indices mean roots: a^(1/2) = √a because squaring a^(1/2) gives a, and a^(1/3) = ∛a. The general power a^(m/n) = (√ⁿa)ᵐ — root first, then power, which keeps the numbers small: 8^(2/3) = (∛8)² = 2² = 4.
Negative and fractional combine: 27^(−1/3) = 1⁄∛27 = 1⁄3, and 16^(−3/4) = 1⁄(⁴√16)³ = 1⁄8. Evaluate the root before the power whenever you can — √16 = 4 then 4³ is friendlier than 16³ then a cube root.
Notes · 3 of 5
Surds: simplifying, multiplying and rationalising
Exact roots stay as roots — pull out square factors and clear denominators. (Higher)
A surd is an exact root that is not a whole number, like √2 or √5. The rule √(ab) = √a × √b lets you extract square factors: √12 = √4 × √3 = 2√3, √50 = 5√2, √72 = 6√2. Surds add only when they are the same surd: √27 + √12 = 3√3 + 2√3 = 5√3, just like 3x + 2x. Multiplying follows the same law: √8 × √6 = √48 = 4√3, and bracket expansions work as normal — (2 + √3)(2 − √3) = 4 − 3 = 1, because the surd terms cancel.
Rationalising removes a surd from a denominator. For a single surd, multiply top and bottom by it: 1⁄√3 = √3⁄(√3 × √3) = √3⁄3. For a bracket like 3 − √2, multiply by the conjugate: 1⁄(3 − √2) × (3 + √2)⁄(3 + √2) = (3 + √2)⁄(9 − 2) = (3 + √2)⁄7, since (a − √b)(a + √b) = a² − b. The answer must always end with a rational (surd-free) denominator.
Notes · 4 of 5
Exact calculations with surds and π
When a question says “exact”, the surd or the π stays.
Non-calculator papers ask for exact answers: leave π as π and surds as surds. A circle of radius 6 cm has circumference 2π × 6 = 12π cm — writing 37.7 cm is a rounded, not exact, answer. Sums mix shapes: √2 + √8 = √2 + 2√2 = 3√2, and ½ × √3 × 4 = 2√3. Fractions stay exact too: 2⁄7 + 1⁄3 = 13⁄21. When a calculator question says “give your answer as a multiple of π”, the π still stays in the final line.
Know which values are nice: (√2)² = 2, (2√5)² = 20, π² stays as π² (it is not 2π). Comparing sizes is fair game: π ≈ 3.14 so 3π ≈ 9.42, which sits between √81 = 9 and √144 = 12. Estimates come from rounding to one significant figure, but an “exact” answer and an “estimate” answer are different questions — read the command.
Notes · 5 of 5
Standard form
A × 10ⁿ with 1 ≤ A < 10 — the scientist’s shorthand, tested hard at GCSE.
Standard form writes a number as A × 10ⁿ where 1 ≤ A < 10 and n is a whole number. Counting place values converts: 4 500 000 = 4.5 × 10⁶ (the point moved six places) and 0.00072 = 7.2 × 10⁻⁴ (four places the other way). Big numbers take positive indices; small numbers take negative ones. A number like 23 × 10⁴ is not standard form because 23 is not between 1 and 10 — rewrite it as 2.3 × 10⁵.
To multiply, multiply the A values and add the indices: (3 × 10⁵) × (4 × 10⁻²) = 12 × 10³ = 1.2 × 10⁴ (re-normalise because 12 is not allowed). To divide, divide the A values and subtract the indices: (8 × 10⁷) ÷ (2 × 10³) = 4 × 10⁴. For addition and subtraction, match the powers of ten first: 2.5 × 10⁶ + 3.7 × 10⁵ = 25 × 10⁵ + 3.7 × 10⁵ = 28.7 × 10⁵ = 2.87 × 10⁶. Keep Calculator papers honest: give final answers in standard form when the question says so, with the right number of significant figures when it does not.
Revise
Key terms
The words examiners expect you to use precisely.
- Index (power)
- The small raised number counting repeated multiplication.In 2⁵ the index is 5.
- Zero index
- The result a⁰ = 1 for any non-zero base.7⁰ = 1.
- Reciprocal
- One divided by the value; what a negative index produces.3⁻² = 1⁄9.
- Surd
- An exact root that is irrational, left in root form.√2, 2√3.
- Rationalise the denominator
- Rewrite a fraction so its denominator contains no surd.1⁄√3 = √3⁄3.
- Conjugate
- The matching bracket with the opposite sign, used to rationalise.3 + √2 is the conjugate of 3 − √2.
Show 1 more key termShow fewer key terms
- Standard form
- A number written as A × 10ⁿ with 1 ≤ A < 10 and n a whole number.4 500 000 = 4.5 × 10⁶.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Multiplying the bases and the indices: 2³ × 2⁴ = 4⁷.
The base stays the same when powers of the same number multiply.
Instead: 2³ × 2⁴ = 2⁷ = 128.
Mistake: Adding indices for a power of a power: (3²)³ = 3⁵.
Raising a power to a power repeats the block, so indices multiply.
Instead: (3²)³ = 3⁶ = 729.
Show 10 more mistakesShow fewer mistakes
Mistake: Treating 7⁰ as 0 or 7.
The subtract rule forces a⁰ = 1.
Instead: 7³ ÷ 7³ = 7⁰ = 1.
Mistake: Reading −2² as (−2)².
Without brackets the power applies only to the 2.
Instead: −2² = −4 but (−2)² = 4.
Mistake: Writing a⁻ⁿ as a negative number.
The negative index means reciprocal, not sign change.
Instead: 3⁻² = 1⁄9, a positive quantity.
Mistake: Halving the base for a square root inside a power: 16^(3/4) = 16^(0.75) → 12.
The denominator is a root, not a division of the value.
Instead: ⁴√16 = 2, then 2³ = 8.
Mistake: Combining √2 + √3 into √5.
Unlike surds do not add, just like unlike terms.
Instead: √2 + √3 stays as it is; √2 + √8 = 3√2 because both become multiples of √2.
Mistake: Simplifying √12 as 2√6.
The square factor pulled out must itself be squared when checked.
Instead: √12 = √4 × √3 = 2√3, since (2√3)² = 12.
Mistake: Rationalising by multiplying only the denominator.
Multiplying top and bottom equally is what preserves the value.
Instead: Multiply numerator and denominator by the surd or conjugate.
Mistake: Leaving a “standard form” answer as 23 × 10⁴.
A must sit between 1 and 10.
Instead: 23 × 10⁴ = 2.3 × 10⁵.
Mistake: Forgetting the double negative when dividing: 6 × 10⁹ ÷ 1.5 × 10⁻² = 4 × 10⁷.
Dividing subtracts indices, and subtracting a negative adds.
Instead: 10⁹ − (−2) = 10¹¹, so the rate is 4 × 10¹¹.
Mistake: Giving a rounded decimal when the question says “exact”.
Rounding destroys the exactness the mark scheme demands.
Instead: Leave π and surds in the final answer: 12π, 3√2.
Check yourself
Quick quiz
30 questions with instant explanations. About 5 minutes.
Question 1 of 3
- Question 1: current question
- Question 2: not answered
- Question 3: not answered
Apply the multiplication index law
Work out 2³ × 2⁴.
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 3 Practice Paper
30 marks · 40 min · 5 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 3: index laws and the zero index, negative and fractional indices (Higher), simplifying and rationalising surds (Higher), exact calculations with surds and π, and standard form conversions, products and quotients.
Mark scheme
PROChapter 3 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
non-calculator · 1 h 30
Exact fractions, surds and multiples of π expected
Papers 2 and 3
calculator · 1 h 30 each
Non-exact answers to 3 s.f., angles to 1 d.p.
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content
Want a full paper? Try the Paper 1-style (Foundation), Papers 2 & 3 style (Foundation), Paper 1-style (Higher), Papers 2 & 3 style (Higher) sets.
Questions
Frequently asked questions
Which parts of this chapter are Higher only?
Negative and fractional indices, and all the surd work (simplifying beyond recognising, multiplying and rationalising), sit on the Higher tier in the AQA and Edexcel schemes. Standard form and the positive index laws are examined at both tiers.
Do I get a formula sheet for this content?
No. GCSE Maths papers have no formula sheet at all. The index laws are rules you derive from repeated multiplication, so learn them as patterns: add to multiply, subtract to divide, multiply for a power of a power, flip for negative, root for fractional.
When should I leave π in an answer?
Whenever the question asks for an exact answer, or says “give your answer in terms of π”. On the non-calculator paper you have no choice; on calculator papers the accuracy mark depends on following the instruction, so read the command word first.
Why does my standard-form answer need re-normalising?
After multiplying the front numbers you can land outside the 1-to-10 range (for example 12 × 10³). Standard form demands 1 ≤ A < 10, so rewrite as 1.2 × 10⁴. The value is unchanged — you are just tidying the notation, and the final mark often depends on it.
Up next
Chapter 4: Estimation, rounding and bounds