Overview
What you’ll learn
- Convert between fractions, terminating decimals and percentages in both directions, and order mixed FDP lists.
- Convert a recurring decimal to a fraction with the 10ⁿ subtraction method, and divide to check (Higher).
- Use fractions and percentages as operators: find a fraction of an amount and apply a one-step percentage multiplier.
- Express one quantity as a percentage of another, compare quantities with percentages, and work above 100%.
- Find percentage change, undo a percentage change to an original value, and compute simple interest.
- Apply repeated multipliers for compound growth, compound interest and depreciation, and compare with simple interest (Higher).
Specification checklist (AQA 8300 · Edexcel 1MA1 · OCR J560)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 2.1Work interchangeably with terminating decimals and their corresponding fractions (such as 3.5 and 7⁄2, or 0.375 and 3⁄8): convert in both directions and order mixed lists.
- 2.3Interpret fractions and percentages as operators: a fraction of an amount, and a percentage increase or decrease as a single multiplier.
- 2.4Define percentage as “number of parts per hundred”; interpret percentages and percentage changes as fractions or decimals, interpret these multiplicatively, express one quantity as a percentage of another, compare two quantities using percentages, and work with percentages greater than 100%.
- 2.5Solve problems involving percentage increase and decrease and original-value (reverse percentage) problems, including simple interest in financial mathematics.
Higher — Higher tier only
- 2.2Change recurring decimals into their corresponding fractions and vice versa, using algebra to convert. (Higher)
- 2.6Solve problems involving repeated percentage change and compound interest, interpreting the repeated multiplier and comparing it with simple interest. (Higher)
Key points
- 1A percentage is a fraction with denominator 100: 45% = 45⁄100 = 0.45.
- 2To convert a terminating decimal to a fraction, use its place value: 0.375 = 375⁄1000 = 3⁄8.
- 3One-step multipliers: increase by 15% → ×1.15; decrease by 12% → ×0.88.
- 4Reverse percentages divide: after a 20% increase the price is ×1.2 of the original, so divide by 1.2 — never add 20% back on.
- 5Percentage change = actual change ÷ original × 100 — the original, not the new value, is the denominator.
- 6More than 100% is fine: 63 is 140% of 45, and a 30% rise followed by a 30% fall is a 9% net fall (1.3 × 0.7 = 0.91).
- 7Simple interest stays fixed: interest = P × r × n. Compound interest multiplies: P × (1 + r)ⁿ (Higher for the power form).
- 8Recurring decimals convert with subtraction: if x = 0.7̇2̇ then 100x − x = 72, so x = 72⁄99 = 8⁄11 (Higher).
Notes · 1 of 6
Converting between fractions, decimals and percentages
Place value turns terminating decimals into fractions; the hundred bus turns them into percentages.
A terminating decimal stops, and its denominator is a power of ten: 0.375 has three decimal places, so 0.375 = 375⁄1000, which simplifies to 3⁄8. Going the other way, 7⁄8 means 7 ÷ 8 = 0.875. To reach a percentage, scale to a denominator of 100: 0.375 = 37.5%. The fraction–decimal–percentage triangle is worth memorising for the famous values: ½ = 0.5 = 50%, ¼ = 0.25 = 25%, ⅕ = 0.2 = 20%, ⅛ = 0.125 = 12.5%, ⅓ = 0.333… and ⅔ = 0.666… (those last two never terminate — that is exactly why the Higher tier converts them with algebra).
To order a mixed list, convert everything to decimals first: given 0.62, ⅝ and 61%, compare 0.62, 0.625 and 0.61, so 61% < 0.62 < ⅝. Keep fractions as fractions when a question says “give your answer as a fraction” — examiners penalise the wrong form even when the value is right.
Notes · 2 of 6
Recurring decimals as fractions
The 10ⁿ subtraction trick, one line of algebra. (Higher)
A recurring decimal repeats forever, written with dots over the repeating block: 0.7̇ = 0.777… and 0.5̇8̇ = 0.585858… Multiply by the power of ten that shifts one full repeat to the left of the point, then subtract the original: for x = 0.7̇, 10x = 7.7̇, so 10x − x = 7 and x = 7⁄9. For x = 0.5̇8̇, 100x = 58.5̇8̇, so 100x − x = 58 and x = 58⁄99. The repeating block length tells you the multiplier and the denominator: one digit → 9, two digits → 99.
Decimals with a non-repeating head need two shifts: x = 0.16̇ (0.1666…) has one non-repeating digit, so shift past it first. 10x = 1.666…, and 100x = 16.666…, so 100x − 10x = 15, giving 90x = 15 and x = 1⁄6. Always check by dividing back: 1 ÷ 6 = 0.1666… ✓
Notes · 3 of 6
Fractions and percentages as operators
“of” means multiply; an increase or decrease is one multiplication by a multiplier.
Reading a fraction or percentage as an operator turns word problems into one multiplication. “3⁄8 of 56” means 3⁄8 × 56 = 21. “Increase £240 by 15%” means £240 × 1.15 = £276: the multiplier 1.15 keeps the whole amount plus fifteen hundredths more. “Decrease by 12%” keeps 88 parts in every 100, so multiply by 0.88: 85 kg × 0.88 = 74.8 kg. Multipliers compose by multiplication, not addition — a 10% rise then a 10% fall multiplies by 1.1 × 0.9 = 0.99, a net 1% fall, not no change.
Two-stage problems chain the operators: “spends ⅖ of £90, then 25% of the rest” is 90 × ⅖ = £36 spent, £54 left, then 54 × 0.75 = £40.50 kept. Draw the two arrows when the wording stacks — each operator acts on the result of the last.
Notes · 4 of 6
One quantity as a percentage of another
Fraction first, hundred second — and percentages above 100 are normal.
“What percentage is 15 of 48?” builds the fraction 15⁄48, then scales to hundredths: 15⁄48 = 0.3125 = 31.25%. The order matters: “63 as a percentage of 45” is 63⁄45 = 1.4 = 140% — values over 100% say the first quantity is bigger than the second, and they are perfectly good answers. Reversing the fraction answers a different question, so underline which quantity is the “of”.
Comparisons use percentages when the bases differ: Team A wins 21 of 30 matches (70%) and Team B wins 26 of 40 (65%), so A has the better win rate despite fewer wins. Change questions use the same construction with the original value underneath: a price moving from £48 to £54 has changed by 6⁄48 = 12.5%. Dividing by the new price instead is the most common percentage-change error there is.
Notes · 5 of 6
Original-value problems and simple interest
Undo multipliers by division; simple interest adds the same slice every year.
A reverse percentage question gives the after value and asks for the before. Undo the multiplier with division: after a 20% increase, £90 is 1.2 × original, so original = 90 ÷ 1.2 = £75. After a 15% discount, £102 is 0.85 × original, so original = 102 ÷ 0.85 = £120. The classic error adds or subtracts the percentage from the given value — that measures the wrong base and cannot be marked correct, because adding 20% to 90 gives 108, not 75.
Simple interest pays the same slice every period: interest = P × r × n, with r the rate per period and n the number of periods. £600 at 4% per year for 3 years earns 600 × 0.04 × 3 = £72 interest, so the balance is £672. Simple interest is linear — the year-3 interest equals the year-1 interest — which is exactly what distinguishes it from the compound case at Higher.
Notes · 6 of 6
Repeated change and compound interest
The same multiplier, again and again: a power. (Higher)
Higher. When a percentage change repeats, the multipliers multiply: £600 at 4% compound interest for 3 years is 600 × 1.04³ = 600 × 1.124864 = £674.92 (to the nearest penny). Growth and decay use the same shape: a population growing 5% per year multiplies by 1.05 each year; a car losing 15% per year multiplies by 0.85, so £12 000 after two years is 12 000 × 0.85² = £8670. Fractional years follow the same rule — half a year of 4% interest is ×1.04^0.5 on some Higher questions.
The comparison examiners love: £600 at 4% simple interest for 3 years earns 600 × 0.04 × 3 = £72 (balance £672), while compound gives £674.92. Compound wins because each year’s interest itself earns interest. To find how long a value takes to pass a target, test successive powers: 600 × 1.04⁴ = £701.92 but 600 × 1.04⁵ = £730.00 (to 2 d.p.), so a £720 target is passed during the fifth year. Reverse questions — “what rate doubles a value in 10 years?” — solve x¹⁰ = 2 for x, which needs the later indices work.
Revise
Key terms
The words examiners expect you to use precisely.
- Terminating decimal
- A decimal that stops, expressible as a fraction with a power-of-ten denominator.0.375 = 3⁄8.
- Recurring decimal
- A decimal with a digit block repeating forever, written with over-dots.0.7̇2̇ = 8⁄11.
- Multiplier
- The single decimal you multiply by to apply a percentage change.+15% → 1.15; −12% → 0.88.
- Percentage change
- Change divided by the original value, expressed as a percentage.84 → 105 is a 25% increase.
- Reverse percentage
- Finding the original value by dividing by the multiplier.£357 after 15% off → £420.
- Simple interest
- Interest computed only on the original principal, the same amount each period.£600 at 4% for 3 years earns £72.
Show 2 more key termsShow fewer key terms
- Compound interest
- Interest computed on the running balance, equivalent to a repeated multiplier.£600 × 1.04³ = £674.92.
- Depreciation
- Repeated percentage decrease in value over time.£12 000 × 0.85² = £8670.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Converting 0.45 to a fraction as 45⁄10.
Two decimal places mean a denominator of 100, not 10.
Instead: 0.45 = 45⁄100 = 9⁄20.
Mistake: Increasing by 15% by multiplying by 0.15.
0.15 is just the 15% slice, not the whole amount plus the slice.
Instead: Increase by 15% → ×1.15; decrease by 15% → ×0.85.
Show 10 more mistakesShow fewer mistakes
Mistake: Undoing a 20% increase by subtracting 20% from the new value.
The 20% was taken of the original, so it is 20% of a different base.
Instead: Divide by 1.2: £90 ÷ 1.2 = £75.
Mistake: Dividing the change by the new value in a percentage-change question.
Percentage change is measured against the original.
Instead: (new − original) ÷ original × 100.
Mistake: Adding percentage changes across stages: “−30% then −10% = −40%”.
The second change acts on the reduced amount, not the original.
Instead: Multiply the multipliers: 0.7 × 0.9 = 0.63, a 37% cut.
Mistake: Writing a percentage over 100% as impossible.
Percentages compare with the base, and the comparison can exceed it.
Instead: 63 is 140% of 45; a 100% increase doubles a value.
Mistake: Computing simple interest as P × (1 + r)ⁿ.
That is the compound formula.
Instead: Simple interest is P × r × n added once.
Mistake: Rounding 1.04³ to 1.12 before multiplying.
Rounding mid-calculation drifts the final penny.
Instead: Keep 1.124864 in the calculator and round only the final answer.
Mistake: Assuming 0.9̇ equals 0.999… < 1.
The subtraction proof gives 9x = 9, so x = 1 exactly.
Instead: 0.9̇ is exactly 1 — a favourite Higher proof question.
Mistake: Cancelling 72⁄99 to 8⁄11 by dividing by 8.
72 is not divisible by 8; wrong cancellation gives a non-equivalent fraction.
Instead: 72⁄99 divides by the common factor 9: 72⁄99 = 8⁄11.
Mistake: Ordering ⅝ above 0.62 because five eighths “looks bigger”.
Mixed forms cannot be compared directly.
Instead: Convert to decimals: ⅝ = 0.625 > 0.62.
Mistake: Using the compound multiplier for a fractional number of years as if it were a full year.
The power counts periods, and exponents scale continuously.
Instead: Half a year of 4% is ×1.04^0.5, not ×1.02 unless the question says so.
Check yourself
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30 questions with instant explanations. About 5 minutes.
Question 1 of 3
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Convert a terminating decimal to a fraction
Written as a fraction in its simplest form, 0.44 is
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 2 Practice Paper
30 marks · 40 min · 5 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 2: FDP conversions, recurring decimals (Higher), fractions and percentages as operators, one quantity as a percentage of another, percentage change, reverse percentages, simple interest, and compound interest and depreciation (Higher).
Mark scheme
PROChapter 2 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
non-calculator · 1 h 30
Exact fractions, surds and multiples of π expected
Papers 2 and 3
calculator · 1 h 30 each
Non-exact answers to 3 s.f., angles to 1 d.p.
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content
Want a full paper? Try the Paper 1-style (Foundation), Papers 2 & 3 style (Foundation), Paper 1-style (Higher), Papers 2 & 3 style (Higher) sets.
Questions
Frequently asked questions
Is recurring decimals Foundation or Higher?
Converting recurring decimals to fractions is Higher-tier material in the shared DfE content (AQA N10, Edexcel unit on FDP, OCR equivalent). Foundation students work with terminating decimals and percentages only, so everything with over-dots in this chapter carries a Higher tag.
How do I know whether to multiply or divide in a percentage question?
Ask which value is unknown. If you know the original and want the new value, multiply by the multiplier (×1.15 up, ×0.85 down). If you know the new value and want the original, divide by that same multiplier. Reverse-percentage questions are division questions in disguise.
Why is a 10% rise then a 10% fall not back to the start?
Because the fall acts on the larger, risen price. Multipliers multiply: 1.1 × 0.9 = 0.99, so you finish 1% below where you began. This is exactly why chains of percentage changes are written as products, never as sums.
Do I need to memorise the compound interest formula?
There is no formula sheet at GCSE, so yes — understand it rather than recall it blindly: the balance is P × (1 + r⁄100)ⁿ. The Higher questions here check you can build it, square-root it to find a rate, and compare it with simple interest.
Up next
Chapter 3: Indices, surds and standard form