Overview
What you’ll learn
- Convert confidently between metric length, area, volume and capacity units.
- Find perimeters and areas of triangles, parallelograms, trapezia and composite shapes.
- Move fluently between circumference, area, arc length and sector area of circles.
- Calculate volumes and surface areas of prisms and cylinders.
- Apply the sphere and cone formulas (given in questions) to composite solids.
Specification checklist (AQA 8300 · Edexcel 1MA1 · OCR J560)
Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.
Foundation — every student
- 17.1Use standard units of measure and convert between related units of length, area, volume, capacity and mass (mm–cm–m–km, mm²–cm²–m², mm³–cm³–m³, litres–cm³).
- 17.2Find perimeters and areas of 2D shapes: rectangles, triangles, parallelograms, trapezia (Area = ½(a + b)h) and composite shapes built from them.
- 17.3Calculate the circumference (2πr = πd) and area (πr²) of a circle, and the arc length and area of a sector as the appropriate fraction of the whole circle.
- 17.4Calculate the volume and surface area of cuboids, right prisms (cross-section × length) and cylinders (V = πr²h).
Higher — Higher tier only
- 17.5Calculate the surface area and volume of spheres, pyramids, cones and composite solids, using the formulae given in the question where applicable.
Key points
- 1Unit ladders: length steps by 10 (mm→cm→m), area by 100 each step (1 m² = 10 000 cm²), volume by 1000 (1 m³ = 1 000 000 cm³; 1 litre = 1000 cm³).
- 2Perimeter is the walk around the edge; area is the paint inside — never confuse the two.
- 3Memorised areas: triangle ½bh, parallelogram bh, trapezium ½(a + b)h — no formula list exists on GCSE papers.
- 4Circle: circumference 2πr = πd, area πr²; a sector of angle θ° takes a fraction θ⁄360 of both.
- 5Arc length = (θ⁄360) × 2πr; sector area = (θ⁄360) × πr² — same fraction, different whole.
- 6Prism volume = area of cross-section × length; cylinder V = πr²h, total surface area 2πr² + 2πrh.
- 7Higher, formulas given in questions: sphere V = (4⁄3)πr³, S = 4πr²; cone V = (1⁄3)πr²h, curved surface πrl (l = slant height).
- 8A hemisphere has half the volume of its sphere but not half the surface area — the flat circular face must be counted.
Notes · 1 of 4
Units, conversions and perimeter
Length steps by 10, area by 100, volume by 1000.
Metric conversions are powers of ten: 1 m = 100 cm, 1 km = 1000 m. Areas square the length factor — 1 m² = 100² = 10 000 cm² — and volumes cube it: 1 m³ = 100³ = 1 000 000 cm³. Capacity joins through 1 litre = 1000 cm³, so a 0.75-litre bottle holds 750 cm³. Mixing these up is the costliest mensuration slip: an answer “in cm²” that was computed with metres is wrong by a factor of 10 000, not 100.
Perimeter is the total distance around a shape — add every edge, including the ones you must deduce. L-shapes keep a secret: an L cut from a rectangle has the same perimeter as the full rectangle (the notch pushes one horizontal and one vertical edge inward without changing total lengths), while its area drops by the missing rectangle. A 8 cm × 5 cm rectangle with a 3 cm × 2 cm corner removed has perimeter 2(8 + 5) = 26 cm and area 40 − 6 = 34 cm².
Notes · 2 of 4
Areas of triangles, parallelograms and trapezia
Three formulas worth memorising — no formula list exists.
GCSE papers do not print a formula list, so three area formulas live in memory. Triangle: ½ × base × height — the height meets the base at right angles and may fall outside the shape for obtuse triangles. Parallelogram: base × height (it is a sheared rectangle). Trapezium: ½(a + b)h, the two parallel sides averaged, times the perpendicular height between them: parallel sides 7 and 11 with height 6 give ½ × 18 × 6 = 54 cm².
Composite shapes split into rectangles, triangles and trapezia — or, for a frame or ring, subtract the hole from the outer shape. Always mark the dimensions you derive (the far side of an L, the height outside a triangle) on the diagram before calculating; two marks routinely sit on those deductions.
Notes · 3 of 4
Circles: circumference, area, arcs and sectors
One fraction θ⁄360 prices every piece of a circle.
Every circle fact hangs off the radius r: circumference C = 2πr = πd and area A = πr². Keep them distinct by their units — circumference behaves like a length, area like paint. A radius of 6 cm gives C = 12π ≈ 37.7 cm and A = 36π ≈ 113.1 cm². Use the calculator’s π button throughout; early rounding to 3.14 drifts answers out of tolerance.
A sector is a pizza slice of angle θ°, and θ⁄360 is the fraction of the whole circle it represents — of the circumference (the arc) and of the area alike. A 120° sector of a radius-9 circle takes a third: arc = ⅓ × 18π = 6π ≈ 18.8 cm, area = ⅓ × 81π = 27π ≈ 84.8 cm². Reverse questions — find the angle from the arc length — divide by the whole instead of multiplying.
Notes · 4 of 4
Prisms, cylinders — and cones and spheres (Higher)
Cross-section × length for prisms; given formulas for the round solids.
A prism is a 3D shape whose slice stays the same along its length: volume = area of cross-section × length. A cuboid is the simple case (3 × 4 × 10 = 120); a trapezium-shaped trough with cross-section 90 cm² and length 25 cm holds 90 × 25 = 2250 cm³. A cylinder is a circular prism: V = πr²h — a radius-5, height-12 cylinder holds 300π ≈ 942.5 cm³. Surface areas are assembled from flat faces and curves: a cylinder’s total is 2πr² (the two caps) plus 2πrh (the curved wall); a closed 4×3×5 cuboid needs 2(12 + 20 + 15) = 94 cm².
Higher-tier solids come with formulas printed in the question — you apply, not recall. Sphere of radius 3: V = (4⁄3)π(27) = 36π ≈ 113.1 cm³ and S = 4π(9) = 36π ≈ 113.1 cm² (equal here — a curiosity of r = 3). Cone of radius 4, height 3: the slant height l comes from Pythagoras (√(3² + 4²) = 5), then V = (1⁄3)π(16)(3) = 16π ≈ 50.3 cm³ and the curved surface is πrl = 20π ≈ 62.8 cm². Composite solids split into parts — a cylinder with a hemispherical lid needs half the sphere’s volume added, and (for surface area) half the sphere’s curved skin plus the exposed circle, not the hidden one.
Revise
Key terms
The words examiners expect you to use precisely.
- perimeter
- The total distance around the edge of a 2D shape.Add every side, deducing any unlabelled edges.
- composite shape
- A shape built from (or cut out of) simpler shapes.Split and add, or subtract the hole from the whole.
- sector
- The region of a circle between two radii, containing a given angle.Takes a fraction θ⁄360 of the circle’s area.
- arc
- Part of the circumference of a circle cut off by an angle at the centre.Length = (θ⁄360) × 2πr.
- prism
- A 3D solid with a constant cross-section along its length.Volume = cross-section area × length.
- slant height
- The distance from a cone’s edge to its apex along the curved surface.l in the curved surface area πrl; found by Pythagoras from r and h.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Answering an area question with a perimeter (or vice versa).
The units disagree: cm walk the edge, cm² paint the inside.
Instead: Check the unit of the answer requested before choosing the formula.
Mistake: Computing a triangle’s area as b × h.
The right-angled half is missing.
Instead: Area = ½bh; the triangle is half its bounding rectangle.
Show 10 more mistakesShow fewer mistakes
Mistake: Applying ½(a + b)h with the slanted side as the height.
The formula needs the perpendicular distance between the parallel sides.
Instead: h must meet both parallel sides at 90°.
Mistake: Using the diameter in πr².
The area formula wants the radius.
Instead: A 12 cm diameter gives r = 6 and A = 36π, not 144π.
Mistake: Scaling a sector by the angle in the wrong place.
The fraction θ⁄360 multiplies the whole-circle measure.
Instead: Arc = fraction × 2πr; sector area = fraction × πr².
Mistake: Swapping arc length and sector area formulas.
One is a piece of circumference, the other a piece of area.
Instead: Arc scales 2πr; sector scales πr².
Mistake: Converting cm² → m² with a factor of 100.
Each of the two dimensions converts, squaring the factor.
Instead: 1 m² = 10 000 cm²; 1 cm² = 0.0001 m².
Mistake: Converting m³ → cm³ with a factor of 1000.
Three dimensions convert, cubing the factor.
Instead: 1 m³ = 1 000 000 cm³; 2.5 m³ = 2 500 000 cm³.
Mistake: Writing the cylinder volume as πdh.
The cross-section is a circle of area πr², not a line.
Instead: V = πr²h; with a diameter given, halve it first.
Mistake: Halving a sphere’s surface area for a hemisphere.
The flat circular face is exposed once the sphere is cut.
Instead: Hemisphere surface = 2πr² (curved) + πr² (flat) = 3πr².
Mistake: Putting the vertical height into πrl for a cone.
The curved surface unrolls along the slant, not the axis.
Instead: Find l by Pythagoras: l = √(r² + h²).
Mistake: Substituting 3.14 for π before calculating.
Early rounding shifts every answer slightly out of tolerance.
Instead: Use the calculator π key; round only the final answer.
Check yourself
Quick quiz
30 questions with instant explanations. About 5 minutes.
Question 1 of 3
- Question 1: current question
- Question 2: not answered
- Question 3: not answered
Find a rectangle’s perimeter
The perimeter of a 6 cm by 9 cm rectangle is
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Practise
Topical questions
18 exam-style questions with model answers and mark schemes.
A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.
Practise topical questionsExam practice
Practice paper
A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 17 Practice Paper
30 marks · 40 min · 5 pages
10 multiple-choice questions and structured questions with answer lines. Chapter 17: metric unit conversions, perimeter and area of rectilinear shapes, triangles, parallelograms and trapezia, circle circumference and area, arc lengths and sector areas, prism and cylinder volumes and surface areas, and (Higher) cones, spheres and composite solids.
Mark scheme
PROChapter 17 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
How is this chapter examined?
Paper 1
non-calculator · 1 h 30
Exact fractions, surds and multiples of π expected
Papers 2 and 3
calculator · 1 h 30 each
Non-exact answers to 3 s.f., angles to 1 d.p.
Tiers
Foundation (grades 1–5) · Higher (grades 4–9)
Higher assumes all Foundation content
Want a full paper? Try the Paper 1-style (Foundation), Papers 2 & 3 style (Foundation), Paper 1-style (Higher), Papers 2 & 3 style (Higher) sets.
Questions
Frequently asked questions
Which mensuration formulas must I memorise for GCSE?
Unlike IGCSE, GCSE papers print no formula list. You must recall triangle (½bh), parallelogram (bh), trapezium (½(a + b)h), circle (2πr and πr²), and prism/cylinder volumes (cross-section × length; πr²h). Spheres, cones and pyramids are Higher-only, and their formulas are printed in the question when needed.
How do I remember the area and volume unit conversions?
Match the power to the dimensions. Length converts by 10 each step; area by 10² = 100 (1 m² = 10 000 cm²); volume by 10³ = 1000 (1 m³ = 1 000 000 cm³). Capacity joins through 1 litre = 1000 cm³, so 1 m³ = 1000 litres.
What is the fastest way to handle arc and sector questions?
Compute the fraction θ⁄360 once, then apply it twice if needed: to the circumference 2πr for the arc, and to the area πr² for the sector. Keeping everything in terms of π until the last step avoids rounding drift and often cancels entirely in reverse (find-the-angle) questions.
How do I approach a composite solid like a silo?
Split it into named parts — usually a prism or cylinder plus a hemisphere or cone — and volume each part before adding. For surface area, only count faces that actually show: the circle where a hemisphere sits on a cylinder is hidden and must be left out. Volume halves for a hemisphere; surface area does not.
Up next
Chapter 18: Circles and circle theorems