Chapter 9AlgebraAQA · Edexcel · OCRFoundation + HigherNot yet teacher-reviewed

GCSE Maths Simultaneous & inequalities revision

Solve paired equations by elimination and substitution — including the Higher linear/quadratic pairs — then handle inequalities on number lines, quadratic inequality ranges and shaded graph regions.

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9chapter
quiz questions
30quiz questions
topical questions
18topical questions
paper · 40 min
30-markpaper · 40 min

Not yet teacher-reviewed. Written by the QuizQuip team against the DfE GCSE subject content; a teacher has not checked it yet. Spotted a mistake? Tell us

Overview

What you’ll learn

  • Solve linear simultaneous equations by elimination, scaling one or both equations when needed.
  • Solve linear simultaneous equations by substitution, and check the solution in both equations.
  • Solve a linear–quadratic pair by substitution and interpret each solution as a crossing point (Higher).
  • Solve linear inequalities and show solution sets on number lines with correct endpoints.
  • Solve quadratic inequalities and describe shaded regions with set notation (Higher).
  • Read approximate solutions of simultaneous equations from a graph.

Specification checklist (AQA 8300 · Edexcel 1MA1 · OCR J560)

Statements are paraphrased from the shared DfE subject content and grouped by tier. Foundation content is studied by every student; Higher statements are examined on Higher-tier papers only. QuizQuip is not affiliated with AQA, Pearson Edexcel or OCR.

Foundation — every student

  • 9.1Solve two linear simultaneous equations in two variables algebraically, by elimination or substitution, and check the solution in both original equations.
  • 9.3Solve linear inequalities in one variable and represent the solution set on a number line, using the correct open and closed endpoints.
  • 9.5Find approximate solutions to simultaneous equations using their graphs.

Higher — Higher tier only

  • 9.2Solve two simultaneous equations where one is linear and one is quadratic, using substitution, and interpret the pairs of solutions. (Higher)
  • 9.4Solve quadratic inequalities in one variable, and represent linear inequalities in two variables as regions on a graph, using set notation. (Higher)

Key points

  1. 1Elimination: add or subtract the equations so one letter cancels; scale an equation first if the coefficients do not match.
  2. 2Substitution: when one equation gives y = …, replace y in the other equation.
  3. 3Check every simultaneous solution in both original equations.
  4. 4Multiplying an inequality by a negative number flips the sign: −2x ≥ 6 means x ≤ −3.
  5. 5A quadratic inequality splits the number line at the roots: x² − 5x + 6 ≤ 0 gives 2 ≤ x ≤ 3 (Higher).
  6. 6On graphs, dashed lines exclude (< or >) and solid lines include (≤ or ≥) (Higher).
  7. 7A line and a parabola can meet twice — a linear/quadratic pair often has two solution pairs (Higher).
  8. 8On a graph, the crossing point of two lines is the simultaneous solution — read it approximately.

Notes · 1 of 4

Solving by elimination

Add or subtract the equations to wipe out one letter.

For 2x + y = 11 and 3x − y = 9, adding the equations cancels y: 5x = 20, so x = 4 and (from 2 × 4 + y = 11) y = 3. When the coefficients do not match, scale one equation first: 4x + 3y = 10 and 2x + 3y = 8 subtract to give 2x = 2, so x = 1 and y = 2.

Sometimes both equations need scaling. For 3x + 2y = 12 with 5x − 2y = 4, adding works directly (8x = 16, x = 2, y = 3). But for 2x + 3y = 12 and 3x + 4y = 17, multiply the first by 3 and the second by 2: 6x + 9y = 36 and 6x + 8y = 34, so y = 2 and x = 3. Always finish by checking in both original equations — 2(3) + 3(2) = 12 ✓ and 3(3) + 4(2) = 17 ✓.

Notes · 2 of 4

Solving by substitution

When one letter is already isolated, feed it through. (Linear–quadratic: Higher)

When an equation reads y = x + 1, substitute into the other: 3x + 2y = 12 becomes 3x + 2(x + 1) = 12, so 5x = 10, x = 2, y = 3. Substitution is also the method for a linear–quadratic pair (Higher): with y = 2x and x² + y² = 45, substitute to get x² + 4x² = 45, so x² = 9 and x = 3, y = 6 or x = −3, y = −6 — two crossing points, both valid.

Another Higher staple: y = x² and y = 3x + 4? No — take y = x² with y = x + 2: x² = x + 2 gives x² − x − 2 = 0, so (x − 2)(x + 1) = 0 and the solution pairs are (2, 4) and (−1, 1). Each x needs its own y — quoting one y for both x’s loses marks.

Notes · 3 of 4

Linear inequalities on a number line

Solve like an equation — then mind the flip and the endpoints.

Inequalities solve exactly like equations except when you multiply or divide by a negative: −2x ≥ 6 means x ≤ −3, sign flipped. For 3x + 2 < 11, subtract and divide to get x < 3. Compound inequalities squeeze from both sides: 5 ≤ 2x + 1 < 9 means 4 ≤ 2x < 8, so 2 ≤ x < 4.

On a number line, strict inequalities get an open circle (x < 3) and inclusive ones a filled circle (x ≥ 2). Integer lists come from the picture: the integers satisfying 2 ≤ x < 4 are just 2 and 3. In words: “x is at least 2 but less than 4” — the ends are described by the symbols, not by guesswork.

Notes · 4 of 4

Quadratic inequalities and graph regions

Split at the roots; shade the side that works. (Higher)

Higher. A quadratic inequality splits the line at its roots. x² − 5x + 6 ≤ 0: roots 2 and 3, and the quadratic is negative between them, so 2 ≤ x ≤ 3. x² − 4 > 0: roots ±2, and the quadratic is positive outside, so x < −2 or x > 2. Sketching the parabola turns every such question into a picture: below the axis between the roots, above it outside.

Regions in two variables: y < x + 2 is everything below the dashed line y = x + 2 (dashed because equality is excluded); y ≥ 2x − 1 is the solid line plus the region above it. For a pair of inequalities, shade both and keep the overlap. Set notation writes the answers: {x : x > 3}, or {x : 2 ≤ x < 4} for a compound — the colon reads “such that”.

Revise

Key terms

The words examiners expect you to use precisely.

Simultaneous equations
A pair of equations satisfied by the same variable values.2x + y = 11 with 3x − y = 9.
Elimination
Adding or subtracting equations to cancel one variable.Adding cancels +y and −y.
Substitution
Replacing a variable using another equation.y = x + 1 into 3x + 2y = 12.
Solution set
All values that make an inequality true.x < 3 on a number line.
Set notation
Writing a solution set as {x : condition}.{x : 2 ≤ x < 4}.
Region
The part of a graph satisfying one or more inequalities.Below a dashed line.
Show 1 more key term
Strict inequality
A < or > comparison, drawn with open circles or dashed lines.x < 3 excludes 3.

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Subtracting equations that should be added: 2x + y = 11 and 3x − y = 9 solved by subtraction.

    Subtraction makes 2y appear; only addition cancels +y with −y.

    Instead: Add to eliminate opposite coefficients.

  • Mistake: Scaling only one side of an equation.

    Both sides must be multiplied by the same number.

    Instead: 3 × (2x + 3y) = 3 × 12 gives 6x + 9y = 36.

Show 10 more mistakes
  • Mistake: Giving x but not y in a simultaneous solution.

    The answer is a pair of values.

    Instead: Substitute back to find both, then check both equations.

  • Mistake: Quoting one solution pair for a line–parabola system.

    A line usually cuts a parabola twice.

    Instead: Each root of the substituted quadratic gives its own pair: (2, 4) and (−1, 1).

  • Mistake: Keeping the inequality sign when dividing by −2.

    Multiplying or dividing by a negative flips the symbol.

    Instead: −2x ≥ 6 → x ≤ −3.

  • Mistake: Filling the circle for x < 3 on a number line.

    Strict inequalities exclude the endpoint.

    Instead: Open circle at 3; filled circle for x ≤ 3.

  • Mistake: Writing the solution of x² − 5x + 6 ≤ 0 as x ≤ 2 or x ≤ 3.

    The quadratic is only ≤ 0 between the roots.

    Instead: 2 ≤ x ≤ 3.

  • Mistake: Writing x² − 4 > 0 as −2 < x < 2.

    The quadratic is positive outside the roots, not between.

    Instead: x < −2 or x > 2.

  • Mistake: Drawing a solid line for y < x + 2.

    Strict inequalities exclude the boundary.

    Instead: Dashed line for < and >; solid for ≤ and ≥. (Higher)

  • Mistake: Substituting x from a quadratic into the wrong equation order.

    Order still matters for clarity, and mixing lines mid-way causes errors.

    Instead: Substitute the linear expression into the quadratic, solve, then find y from the linear equation.

  • Mistake: Reading a graph crossing as an exact solution.

    Graphs give approximations.

    Instead: “x ≈ 3, y ≈ 5 (from the graph)”.

  • Mistake: Forgetting to test the solution in the equation that was not used.

    Arithmetic slips survive one check but not two.

    Instead: Check x and y in both original equations.

Check yourself

Quick quiz

30 questions with instant explanations. About 5 minutes.

Question 1 of 3

  1. Question 1: current question
  2. Question 2: not answered
  3. Question 3: not answered

Eliminate a variable by adding

Solving 2x + y = 11 and 3x − y = 9 by adding gives

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Practise

Topical questions

18 exam-style questions with model answers and mark schemes.

A set of structured and calculation questions matched to this chapter, in three tiers, each with a model answer, mark scheme and examiner tip. Higher-tier questions are tagged.

Practise topical questions

Exam practice

Practice paper

A 30-mark paper in the style of a GCSE paper, with a separate mark scheme. Give yourself 40 min.

Question paper

Chapter 9 Practice Paper

30 marks · 40 min · 5 pages

10 multiple-choice questions and structured questions with answer lines. Chapter 9: simultaneous equations by elimination and substitution, linear–quadratic pairs (Higher), linear inequalities on number lines, quadratic inequalities and graph regions with set notation (Higher), and approximate solutions from graphs.

Mark scheme

PRO

Chapter 9 Practice Paper — mark scheme

Answers · Marking points · 3 pages

Model answers with a mark for each creditworthy point — for marking at home or in class.

Print view

How is this chapter examined?

Paper 1

non-calculator · 1 h 30

Exact fractions, surds and multiples of π expected

Papers 2 and 3

calculator · 1 h 30 each

Non-exact answers to 3 s.f., angles to 1 d.p.

Tiers

Foundation (grades 1–5) · Higher (grades 4–9)

Higher assumes all Foundation content

Want a full paper? Try the Paper 1-style (Foundation), Papers 2 & 3 style (Foundation), Paper 1-style (Higher), Papers 2 & 3 style (Higher) sets.

Questions

Frequently asked questions

Which parts of this chapter are Higher only?

Linear simultaneous equations, linear inequalities and graphical approximate solutions are common to both tiers. Linear–quadratic pairs, quadratic inequalities, regions on graphs and set notation are Higher-tier.

How do I choose between elimination and substitution?

If a letter is already isolated (y = 2x), substitute. If both equations are in the form ax + by = c, eliminate — scale one equation until a pair of coefficients matches, then add or subtract. In an exam the question usually rewards whichever is quicker for that pair.

Why does the inequality sign flip?

Because dividing by a negative reverses the order of numbers: −2 < −1 but 2 > 1 after dividing by −1. The flip happens for multiplication and division by negatives only — adding and subtracting never flips.

How many crossing points can a line and a parabola have?

Up to two, because substituting the line into the parabola gives a quadratic. Two real roots means two crossing points (and two solution pairs); a negative discriminant means the line misses the curve entirely.

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Chapter 10: Sequences

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