Overview
What you’ll learn
- State that rate is the change of a measurable quantity (gas volume, mass loss, colour or precipitate) per unit time, and describe how each is measured experimentally.
- Explain rate changes using collision theory: reacting particles must collide with at least the activation energy.
- Predict and explain the effects of concentration, pressure, particle size (surface area), temperature, catalysts and light on the rate of reaction.
- Interpret rate graphs: gradient as rate, curves levelling off when the limiting reactant is used up, and comparing experiments run under different conditions.
- Apply the molar gas volume (24 dm³ at r.t.p.) to calculate the final gas volume expected from a given mass of reactant.
In 30 seconds
- 1Rate = change in quantity ÷ time taken; on a graph the gradient is the rate — steep means fast, flat means finished.
- 2Collision theory: particles must collide, and collide with at least the activation energy, for reaction.
- 3Concentration ↑ or pressure ↑ → more particles per unit volume → more frequent collisions → faster rate.
- 4Smaller particle size (powder) bigger surface area per gram → more exposed particles → more frequent collisions → faster rate.
- 5Temperature ↑ works twice: particles move faster (more frequent collisions) and more collisions clear the activation energy — the second effect dominates.
- 6A catalyst lowers Eₐ so more collisions succeed; it is not consumed and does not change the final yield.
- 7Light drives photochemical reactions: silver bromide darkens (2AgBr → 2Ag + Br₂) and photosynthesis needs sunlight.
- 8Rate graphs level off when the limiting reactant runs out — the plateau volume identifies how much gas the limiting reagent can give (via 24 dm³/mol at r.t.p.).
Notes · 1 of 5
Measuring how fast
Pick a quantity that changes — gas, mass, colour — and plot it against time.
Rate is always how much changes, divided by how long it takes: rate = Δquantity ÷ Δtime. For a gas-producing reaction (marble in acid), collect the gas in a gas syringe and plot volume against time; for a reaction that loses gas to the air (carbonate + acid on an open balance), plot mass loss against time; for the sodium thiosulfate “disappearing cross”, time how long the precipitate takes to hide a cross beneath the beaker.
| Reaction type | What you measure | Apparatus |
|---|---|---|
| Metal + acid (H₂ given off) | Gas volume vs time | Gas syringe |
| Carbonate + acid (open system) | Mass loss vs time | Balance + cotton wool plug |
| Thiosulfate + acid (cloudy sulfur) | Time for cross to disappear | Cross on paper under beaker |
| Any colour change | Colour intensity vs time | Eyes or a colorimeter |
Notes · 2 of 5
Collision theory
Two conditions per collision: they must meet, and they must meet hard enough.
Reactions happen when reactant particles collide — but only collisions carrying at least the activation energy succeed. Every rate factor therefore works through just two levers: how often particles collide (collision frequency) and what fraction of collisions clear Eₐ (collision energy).
This is the explanation template for every factor: name the factor’s physical effect, convert it to collision frequency or collision energy, then conclude the rate change. More frequent successful collisions each second mean a faster reaction.
Notes · 3 of 5
Concentration, pressure and particle size
Crowding particles together speeds them up; grinding them up exposes more of them.
A more concentrated solution packs more particles into each dm³, so collisions per second rise and the rate climbs. The same logic compressed: for gases, raising the pressure squeezes the same particles into less volume — same result, faster reaction. (A classic hospital-rate analogy: a crowded corridor produces more shoulder-bumps per second than an empty one.)
Particle size is surface area in disguise: one big lump hides most of its particles inside, while grinding it into powder exposes nearly all of them. Marble chips fizzle politely in hydrochloric acid; the same mass of marble powder froths violently — then both curves level at the same final volume, because the amount of CaCO₃ never changed.
Notes · 4 of 5
Temperature, catalysts and light
Heat works twice; catalysts cut the toll; light drives the photochemical few.
A 10 °C rise can roughly double a reaction rate. Temperature works through both levers: particles move faster (slightly more frequent collisions) and — the big one — a much larger fraction of collisions now exceeds Eₐ. The energy shift beats the frequency shift, which is why heating is the chemist’s favourite accelerator.
A catalyst offers a lower-energy route: Eₐ drops, so a bigger share of collisions succeed at the same temperature. Manganese(IV) oxide, MnO₂, decomposes hydrogen peroxide at room temperature: 2H₂O₂ → 2H₂O + O₂ — the splint test confirms oxygen roaring out, and the black powder is recovered unchanged afterwards.
Light is the rarest rate factor: photochemical reactions use photons as their energy source. Silver bromide in film darkens in light (2AgBr → 2Ag + Br₂), which is why film is sold in black canisters; photosynthesis runs on sunlight and stops in the dark.
Notes · 5 of 5
Reading rate graphs
Gradient is rate; the plateau is the limiting reactant’s signature.
On a gas volume–time curve, the steeper the gradient, the faster the reaction. Every curve starts steep and flattens as reactants are used up — collisions keep happening but successful ones become rare. The flat region means the reaction is over: the limiting reactant is exhausted.
Compare curves like a forensic scientist: same plateau, steeper start same amount, faster conditions (powder vs chips, hotter vs colder, concentrated vs dilute). Different plateaus different amounts of limiting reactant. To turn a plateau into moles, use the r.t.p. molar gas volume: 24 dm³ = 24 000 cm³ per mole.
Revise
Key terms
The words examiners expect you to use precisely.
- Rate of reaction
- The change in a measured quantity (gas volume, mass, colour) per unit time.
- Collision theory
- Reactants react only when particles collide with at least the activation energy.
- Activation energy (Eₐ)
- The minimum collision energy needed for a collision to result in reaction.
- Collision frequency
- The number of collisions per second; raising concentration, pressure, surface area or temperature increases it.
- Surface area
- The exposed area of solid reactant; powdering increases it and speeds the reaction.
- Catalyst
- A substance that speeds a reaction by lowering Eₐ and is recovered unchanged at the end.
Show 6 more key termsShow fewer key terms
- Photochemical reaction
- A reaction driven by light, e.g. silver bromide darkening or photosynthesis.
- Gas syringe
- A sealed barrel that measures the volume of gas evolved in a rate experiment.
- Limiting reactant
- The reactant that runs out first; its exhaustion causes the rate graph to plateau.
- Initial rate
- The rate at the very start of the reaction, found from the steepest early tangent.
- Average rate
- Total change divided by total time, e.g. 48 cm³ in 2.0 min = 24 cm³/min.
- Molar gas volume (r.t.p.)
- One mole of any gas occupies 24 dm³ (24 000 cm³) at room temperature and pressure.
Revise
Common mistakes
Where students most often lose marks in this chapter — and what to do instead.
Mistake: Saying higher concentration makes particles "hit harder".
Concentration crowds particles; it does not energise them.
Instead: More particles per volume → more frequent collisions; only temperature raises collision energy.
Mistake: Claiming powder reacts faster because it "dissolves more easily".
The acid is not about solubility.
Instead: Powder exposes a larger surface area, raising collision frequency.
Show 10 more mistakesShow fewer mistakes
Mistake: Expecting powdered marble to give more CO₂ than chips.
Same mass means same moles means same final gas volume.
Instead: Powder changes the rate only; the plateau volume is identical.
Mistake: Reading the rate from the plateau level.
The plateau is the total amount; the rate is the gradient.
Instead: Steeper gradient = faster rate; flat = reaction over.
Mistake: Saying a catalyst gets used up or appears in the final equation.
Catalysts are recovered unchanged.
Instead: The catalyst sits above the arrow (MnO₂ over 2H₂O₂ → 2H₂O + O₂), not in it.
Mistake: Explaining temperature only as "particles move faster".
That is only half the story — and the smaller half.
Instead: More frequent collisions AND a much larger fraction exceeding Eₐ.
Mistake: Using the initial rate where the average rate is asked.
The initial tangent is steeper than the overall average.
Instead: Average rate = total change ÷ total time; initial rate = first tangent; state which you quote.
Mistake: Forgetting the cotton wool on the balance in mass-loss experiments.
Acid spray escaping would fake a bigger mass loss.
Instead: Cotton wool lets gas out but blocks droplets.
Mistake: Converting gas volumes with 24 cm³ per mole.
Off by a factor of a thousand.
Instead: 24 dm³ = 24 000 cm³ per mole at r.t.p.
Mistake: Saying increasing pressure affects reactions in solution.
Liquids are practically incompressible.
Instead: Pressure matters for gaseous reactants only.
Mistake: Treating light as a catalyst.
Light is an energy source that gets absorbed, not a substance recovered unchanged.
Instead: Photochemical reactions consume photons; catalysts provide a lower-Eₐ path.
Mistake: Drawing the faster-condition curve with a higher plateau "because it is faster".
Speed and amount are independent.
Instead: Faster conditions steepen the curve; only more limiting reactant raises the plateau.
Check yourself
Quick quiz
20 questions with instant explanations. About 5 minutes.
Question 1 of 3
- Question 1: current question
- Question 2: not answered
- Question 3: not answered
Define rate
Rate of reaction is best defined as
Ready for more practice on Chapter 4: Rate of Reactions?
Generate a fresh 5-question drill built from this chapter’s key points. Free with your study account.
Practise
Topical questions
Exam-style practice in three tiers, from recall to data questions.
- 4Foundation
- 5Standard
- 3Challenging
12 questions worth 49 marks, each with a model answer, mark scheme and examiner tips.
Practise topical questionsExam practice
Practice paper
A 30-mark paper set out like a school paper, with a separate mark scheme. Give yourself 40 min.
Question paper
Chapter 4 Practice Paper
30 marks · 40 min · 5 pages
5 multiple-choice questions and structured questions with answer lines. Chapter 4 (measuring rates, collision theory, rate factors, graph interpretation).
Mark scheme
PROChapter 4 Practice Paper — mark scheme
Answers · Marking points · 3 pages
Model answers with a mark for each creditworthy point — for marking at home or in class.
Where this chapter is tested
Each school sets its own scope — check your assessment outline.
Questions
Frequently asked questions
What does Sec 4 Chemistry Chapter 4 cover?
It covers sub-topic 3.6 of O-Level Pure Chemistry 6092: measuring rates (gas syringe, mass loss, disappearing cross), collision theory, the six rate factors (concentration, pressure, surface area, temperature, catalysts, light), and how to read and compare rate graphs including the r.t.p. molar gas volume.
How do I remember which factors raise collision frequency and which raise collision energy?
Crowding factors — concentration, pressure, surface area — raise how OFTEN particles meet. Only temperature raises how HARD they meet (plus a little frequency). Catalysts change neither: they lower the energy bar itself.
Why do two rate curves finish at the same level but start differently?
Because the amount of limiting reactant decides the plateau, while the conditions decide the steepness. Powder vs chips, hot vs cold, concentrated vs dilute all change the journey, not the destination.
How do I convert a plateau reading into moles?
Use the r.t.p. molar volume: moles of gas = volume in dm³ ÷ 24 (or cm³ ÷ 24 000). Then apply the mole ratio from the balanced equation to reach the limiting reactant.
When is this chapter usually tested in school?
Rate of reactions sits mid-Sec 4 and is a fixture of prelim Paper 2 — usually as a graph-interpretation question fused with mole calculations. Scope varies by school, so check your school’s assessment outline.
Up next
Chapter 5: Ammonia and Reversible Reactions