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Chapter 5Theme 4 · AlgebraG2 / G3

Sec 2 Mathematics Direct & Inverse Proportion notes

Two ways quantities move together: direct proportion climbs in step (y = kx), inverse proportion trades off (y = k/x) — and a constant k secretly runs both.

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Overview

What you’ll learn

  • Recognise direct proportion and write it as y ∝ x, y = kx.
  • Find the constant of proportionality from one pair of values and use it to predict others.
  • Recognise inverse proportion and write it as y ∝ 1/x, y = k/x.
  • Identify a proportional relationship from a table by testing ratios or products.
  • Describe the graphs of direct and inverse proportion.
  • Solve real-world problems involving direct, inverse and squared proportion.

In 30 seconds

  1. 1Direct proportion: both quantities rise and fall in the same ratio — written y ∝ x, with equation y = kx.
  2. 2Inverse proportion: one rises as the other falls so that the product stays constant — y ∝ 1/x, with equation y = k/x.
  3. 3Find k from one known pair of values, then reuse the equation for every other question.
  4. 4A direct-proportion graph is a straight line through the origin; an inverse-proportion graph is a curve approaching both axes.
  5. 5Table test: if the ratios y/x match, it is direct; if the products xy match, it is inverse.
  6. 6Proportional forms can wear other shapes too, such as y ∝ x² — spot the pattern, find k, substitute.

Notes · 1 of 6

Direct proportion

Double one, double the other: the ratio never moves.

Two quantities are in direct proportion when one is always a fixed multiple of the other. Six pens cost three times what two pens cost, because each pen has the same price. In symbols, y ∝ x, and the ∝ becomes an equation with a constant: y = kx.

Pens at a constant price
Pens (x)24610
Cost (y)$3$6$9$15

Every y/x here equals 1.5 — the price per pen, which is exactly the constant k. The unitary method (find one, then scale) and the k-method are the same idea wearing different clothes: k = y ÷ x.

Notes · 2 of 6

The constant k does the predicting

One honest pair of values fixes the whole relationship.

  1. 11. Write the proportion form

    y ∝ x becomes y = kx.

  2. 22. Substitute the known pair

    Put in one full (x, y) pair from the question.

  3. 33. Solve for k

    Divide y by x.

  4. 44. Predict

    Use y = kx with the new value — and state the finished equation.

One pair fixes k: y = 15 when x = 5
StepWorking
Substitute15 = k × 5
Solvek = 3
Equationy = 3x
Predict at x = 12y = 3 × 12 = 36

Notes · 3 of 6

Inverse proportion

More hands, less time: the product is the thing that never changes.

Two quantities are in inverse proportion when one increases by the same factor that the other decreases — doubling the workers halves the time. The fixed quantity is the product: y ∝ 1/x, written as the equation y = k/x, or equivalently xy = k.

Painting a fence with constant work (48 worker-hours)
Workers (x)2468
Days (y)241286

Every product xy equals 48 — the total work in worker-days. That product is the k of the inverse relationship. To predict, compute k from one pair, then either divide (y = k/x) or multiply (x = k/y).

Notes · 4 of 6

Proportional graphs

Direct is a straight line through zero; inverse is a curve dodging both axes.

y = kx is the equation of a straight line through the origin with gradient k: zero x gives zero y, and the line climbs steadily. y = k/x is a very different animal: it sweeps down a curve that approaches both axes without touching them, because dividing by a huge x sends y near 0, and x = 0 itself is forbidden.

Shapes at a glance
RelationshipEquationGraphPasses through origin?
Directy = kxstraight line, gradient kyes
Inversey = k/xcurve approaching both axesno (x = 0 impossible)
Squared formy = kx²upward curve starting at originyes

Notes · 5 of 6

Direct or inverse? Test the table

Matching ratios point to direct; matching products point to inverse.

  1. 11. Divide across

    Compute y ÷ x for every row: all equal → direct proportion.

  2. 22. Multiply across

    Compute x × y for every row: all equal → inverse proportion.

  3. 33. Beware neither

    If neither test passes, the data is not proportional at all.

  4. 44. Write the equation

    State y = kx or y = k/x with your k before answering further parts.

Both tests on one table: (1, 24), (2, 12), (3, 8)
Rowy ÷ xx × y
(1, 24)2424
(2, 12)624
(3, 8)2.67…24

Notes · 6 of 6

Proportion in the real world

Recipes, fuel, timetables and squared surprises — the k-routine handles them all.

Spotting the story behind the problem
ContextRelationshipWhy
Cost of rice by the kilogramdirectunit price is fixed
Workers and days for one jobinversetotal worker-days is fixed
Speed and time over one journeyinversedistance is fixed
Distance fallen and timey ∝ x²physics doubling rule — treat as a squared form

The universal routine survives every context: name the variables, choose the form, find k from one pair, answer with the equation. Only the final step — rejecting impossible values like negative times — needs human judgement.

Revise

Key terms

The words examiners expect you to use precisely.

Direct proportion
A relationship where two quantities increase or decrease in the same ratio: y = kx.
Inverse proportion
A relationship where one quantity rises as the other falls with a constant product: y = k/x.
Constant of proportionality
The fixed number k linking the variables; y ÷ x for direct, x × y for inverse.
Unitary method
Solving by finding the value for one unit first, then scaling.
Proportion symbol (∝)
The “is proportional to” sign; it becomes an equals sign once k is found.
Ratio
A comparison of two quantities by division; constant ratio signals direct proportion.
Show 6 more key terms
Constant product
The fixed value of x × y in inverse proportion, such as worker-days.
Origin
The point (0, 0); a direct-proportion graph always passes through it.
Squared proportion
A form such as y ∝ x², where one quantity varies with the square of the other.
Worker-days
The product of workers and days — the fixed total work in an inverse-proportion job.
Scale factor
The factor by which one quantity is multiplied, forcing the other to follow its rule.
Sanity check
A quick direction test: in direct proportion both quantities climb together; in inverse they trade off.

Revise

Common mistakes

Where students most often lose marks in this chapter — and what to do instead.

  • Mistake: Treating “more workers, fewer days” as direct proportion.

    The quantities move in opposite directions, which is the signature of inverse proportion.

    Instead: Multiply workers by days to get the constant k, then divide for the new case.

  • Mistake: Adding the same amount instead of scaling: “x grows by 2, so y grows by 2”.

    Proportion is multiplicative — ratios, not differences, stay constant.

    Instead: Compute k from a pair, then multiply; check with a second pair before trusting the rule.

Show 8 more mistakes
  • Mistake: Forgetting to find k and guessing the answer by cross-multiplying blindly.

    Working without the equation hides mistakes and earns no method marks.

    Instead: Write y = kx (or y = k/x), substitute the known pair, find k, then answer.

  • Mistake: Claiming the graph of y = k/x touches the x-axis.

    Dividing by a huge x makes y tiny but never zero; x = 0 is impossible.

    Instead: The inverse curve approaches both axes without touching them.

  • Mistake: Using one worker-day value after the team size changes, e.g. keeping 6 days for 12 workers.

    Changing one quantity forces the other to adjust so the product stays fixed.

    Instead: Recompute: k = 6 × 8 = 48, so 12 workers need 48 ÷ 12 = 4 days.

  • Mistake: Reporting a negative or zero answer for time, workers or cost.

    Those quantities have meaningful ranges that the algebra ignores.

    Instead: Keep the root that fits the story and reject the rest with a reason.

  • Mistake: Halving k when the question doubles x in a y ∝ x² problem.

    Squaring doubles the sensitivity: x × 2 multiplies y by 4.

    Instead: Substitute into y = kx² with the new x; never eyeball squared forms.

  • Mistake: Thinking “12 workers instead of 8, so the job takes 4 fewer days”.

    Inverse proportion trades by division, not subtraction — the fixed product decides the new time.

    Instead: k = 8 × 6 = 48, so 12 workers need 48 ÷ 12 = 4 days; the drop is 2 days, not 4.

  • Mistake: Confirming inverse proportion just because y decreases as x increases.

    Plenty of falling tables are not proportional at all: (1, 12), (2, 11), (3, 10) falls but the products 12, 22, 30 are not constant.

    Instead: Inverse requires a constant product x × y — test the products, not the trend.

  • Mistake: Scaling down when the story scales up: “2 pens cost $3, so 6 pens cost $1”.

    Six pens are three times as many, so the cost must triple, not shrink.

    Instead: Multiply by the same scale factor: 6 = 2 × 3, so the cost is 3 × $3 = $9.

Check yourself

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Question 1 of 3

  1. Question 1: current question
  2. Question 2: not answered
  3. Question 3: not answered

Find the equation for direct proportion

y is proportional to x, and y = 12 when x = 3. What is the equation linking y and x?

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Questions

Frequently asked questions

What is Sec 2 Math Chapter 5 about?

Chapter 5 covers direct and inverse proportion: writing y ∝ x as y = kx and y ∝ 1/x as y = k/x, finding the constant k from one pair of values, testing tables, comparing the two graph shapes, and solving real-world problems including squared forms.

How do I tell direct from inverse proportion in a table?

Run two tests. If every y ÷ x gives the same number, the table is direct proportion. If every x × y gives the same number, it is inverse. If neither holds, the data is not proportional.

What does the graph of inverse proportion look like?

A smooth curve that approaches both axes without ever touching them: large x sends y close to zero, and x = 0 itself is impossible because you cannot divide by it. Direct proportion, in contrast, is a straight line through the origin.

How do worker-day problems work?

The total work is fixed: workers × days = k. Find k from the given case, then divide k by the new number of workers to get the new time. Twelve workers with k = 48 finish in 48 ÷ 12 = 4 days.

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