Chapter 4 Practice Paper: Rate of Reactions — question paper
Secondary 4 · Combined Science (Chemistry) (G2 / G3)
Chapter 4 Practice Paper
Rate of Reactions
READ THESE INSTRUCTIONS FIRST
- Answer all questions.
- Section A: choose the one correct answer for each multiple-choice question.
- Section B: answer in the spaces provided; show all necessary working.
- Give numerical answers to 3 significant figures where appropriate, with units.
- A copy of the Periodic Table is printed with real Combined Science papers; it is not needed for this paper.
- The use of a calculator is permitted.
Original practice material written for the MOE Combined Science (Chemistry) syllabus. It is not an official MOE or school examination paper. Chapter 4 (collision theory; effects of concentration, pressure, particle size and temperature; mean rates from gas-volume and mass-loss data; reading rate graphs).
| For Examiner’s Use | |
|---|---|
| Section A | / 10 |
| Section B | / 20 |
| Total | / 30 |
Section A: Multiple-choice questions[10 marks]
Choose the one correct answer for each question.
- 1( )
Which change increases both the frequency and the energy of collisions between reacting particles?
- Aa higher concentration
- Ba higher temperature
- Csmaller solid pieces
- Da higher gas pressure
- 2( )
A gas syringe collects 24 cm³ of gas in 40 s. The mean rate of collection is
- A0.6 cm³/s
- B1.7 cm³/s
- C24 cm³/s
- D40 cm³/s
- 3( )
Pressure is a rate factor that applies to
- Aall reactions
- Breactions involving gases
- Csolid reactions only
- Dsolutions only
- 4( )
The same mass of marble reacts with 1.0 mol/dm³ and with 2.0 mol/dm³ acid (both in excess). Both volume–time curves flatten at 64 cm³. This shows that
- Athe acids were at different temperatures
- Bmore gas formed with the higher concentration
- Cthe same amount of marble reacted in both runs
- Dthe stronger acid made less gas
- 5( )
A large lump of solid reactant is cut into four smaller pieces of the same total mass. The reaction speeds up because
- Athe particles gain energy
- Bthe total mass increases
- Cthe concentration of the solution increases
- Dthe surface area exposed to collisions is larger
Section B: Structured questions[20 marks]
Answer all questions in the spaces provided. Show all necessary working. Give numerical answers to 3 significant figures where appropriate, with units.
- 1
Excess dilute hydrochloric acid reacts with calcium carbonate chips. A gas syringe records the volume of carbon dioxide collected.
Gas volume against time
Time / s 0 20 40 60 80 Volume of CO₂ / cm³ 0 34 52 58 58 - (a)
Calculate the mean rate of gas production over the first 20 seconds, in cm³/s.
mean rate =cm³/s[2] - (b)
State the time at which the reaction finished and explain how the data shows it.
[1] - (c)
Explain why the rate of reaction was fastest at the start.
[2] - (d)
State what the flat final height of 58 cm³ represents.
[1]
- (a)
- 2
A student compares 1.0 g of magnesium ribbon with 1.0 g of magnesium powder. Each is added, separately, to 50 cm³ of the same excess dilute hydrochloric acid at 25 °C, and the time to collect 50 cm³ of hydrogen is measured: ribbon 150 s, powder 40 s.
- (a)
State the variable deliberately changed and two variables kept the same.
[2] - (b)
Explain, using collision theory, why the powder reacted faster.
[2] - (c)
Predict, with a reason, the effect of repeating the ribbon experiment with acid of double the concentration at the same temperature.
[2]
- (a)
- 3
A flask containing dilute hydrochloric acid stands on a balance. A plug of cotton wool is placed in the flask neck, then 0.24 g of magnesium is added quickly and the flask re-weighed as it reacts. The balance reading falls from 120.00 g to 119.64 g in 2.0 minutes and then stays constant.
- (a)
Calculate the mean rate of mass loss over the 2.0 minutes, in g/min.
mean rate =g/min[2] - (b)
State the purpose of the cotton wool plug.
[1] - (c)
Name the gas that escaped and write the equation for its formation.
[2] - (d)
Describe the shape of the mass–time graph between 0 and 2 minutes, and explain the shape using collision theory.
[3]
- (a)
— End of paper —