Topic 6 Practice Paper: Thermal physics — mark scheme
IGCSE · Cambridge IGCSE Physics (Extended (Core + Supplement))
Mark scheme
Thermal physics
Topic 6 Practice Paper · Maximum mark: 30
Notes for markers
- Award one mark for each point marked [1], up to the marks shown for the part.
- Accept answers worded differently that show the same understanding.
- Units are required where the answer line shows one. ecf: allow an error carried forward.
Section A: Multiple-choice questions[10 marks]
| Question | Answer and marking points | Marks |
|---|---|---|
| Total for Question 1 | 1 | |
| Total for Question 2 | 1 | |
| Total for Question 3 | 1 | |
| Total for Question 4 | 1 | |
| Total for Question 5 | 1 | |
| Total for Question 6 | 1 | |
| Total for Question 7 | 1 | |
| Total for Question 8 | 1 | |
| Total for Question 9 | 1 | |
| Total for Question 10 | 1 |
Section B: Structured questions[20 marks]
| Question | Answer and marking points | Marks |
|---|---|---|
| 11(a) | Brownian motion [1] | 1 |
| 11(b) | The invisible air molecules move fast and randomly, bombarding each smoke speck from all sides; uneven numbers of impacts from moment to moment push the speck in changing directions.
| 2 |
| 11(c) | That air is made of tiny particles in constant random motion — the kinetic particle model.
| 1 |
| 11(d) | Microscopic particles (as opposed to the molecules or atoms of the air). [1] | 1 |
| Total for Question 11 | 5 | |
| 12(a) | E = Pt = 42 × 600 = 25 200 J.
| 2 |
| 12(b) | Δθ = ΔE/(mc) = 25 200 ÷ (2.5 × 900) = 25 200 ÷ 2250 = 11.2 °C.
| 2 |
| 12(c) | Some of the electrical energy heats the surroundings (air, insulation) instead of the block, so the block receives less than 25 200 J.
| 2 |
| Total for Question 12 | 6 | |
| 13(a) | 27 °C = 300 K; 12 °C = 285 K.
| 1 |
| 13(b) | Cooler particles move more slowly, so they hit the can’s walls less often and with less force — the force per unit area (pressure) decreases.
| 2 |
| 13(c) | It would fall towards zero as the particles’ kinetic energy falls towards its minimum at absolute zero (−273 °C).
| 1 |
| Total for Question 13 | 4 | |
| 14(a) | Air touching the tea’s surface is warmed, expands, becomes less dense and rises; cooler denser air sinks and replaces it, carrying energy away in a convection current.
| 2 |
| 14(b) | It reduces radiative transfer: the shiny surface reflects the infrared back towards the tea instead of absorbing and re-emitting it, so less radiation escapes.
| 2 |
| 14(c) | Matt black is a better absorber of radiation than shiny silver, so it takes in the tea’s radiated energy faster.
| 1 |
| Total for Question 14 | 5 |
— End of mark scheme —