GCSE (9–1) · GCSE Mathematics (Foundation with Higher stretch)
Chapter 7 Practice Paper
Linear equations and straight-line graphs
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Original practice material written for the MOE GCSE Mathematics syllabus. It is not an official MOE or school examination paper. Chapter 7: solving linear equations with brackets, fractions and unknowns on both sides, y = mx + c, plotting lines, equations through two points, parallel and perpendicular lines (Higher), and approximate solutions from graphs.
| For Examiner’s Use | |
|---|---|
| Section A | / 10 |
| Section B | / 20 |
| Total | / 30 |
Section A: Multiple-choice questions[10 marks]
Choose one answer for each question. Every correct answer scores one mark.
Solve 2x + 7 = 19.
Solve 7x − 4 = 4x + 11.
The gradient of y = 5 − 2x is
The y-intercept of y = ½x + 3 is
From (0, 2) to (4, 10), the gradient of the segment is
Which line below runs parallel to y = −3x + 2?
Solve (3x − 2)⁄4 = 2.
Through the point (1, 6) runs a line of gradient 4. Which equation is it?
Flip-and-negate the gradient of y = −2x + 7: the perpendicular gradient is (Higher)
The lines y = 3x − 1 and y = 3x + 4
Section B: Structured questions[20 marks]
Show all your working. Marks are given for method as well as for the final answer.
Solving equations.
Solve 5(x − 2) = 3x + 8.
Solve (x + 7)⁄2 = 3x.
Lines from points.
Find the equation of the line through (1, 2) and (5, 14).
Does the point (4, 11) lie on this line?
Straight-line graphs.
Complete a table for y = 6 − 2x at x = 0, 1, 2, 3 and state the gradient and intercept.
Write down the coordinates where this line crosses the x-axis.
Meeting at right angles. (Higher)
A line runs perpendicular to y = ⅔x + 1 through the point (4, 9). Find its equation.
Show that the gradients of the two lines multiply to −1.
Linear models. (Higher)
Two heaters warm a room: Heater A raises the temperature by T = 5 + 1.5m degrees after m minutes; Heater B by T = 2m degrees. After how many minutes are they at the same temperature?
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