GCSE (9–1) · GCSE Chemistry (Foundation and Higher)
Chapter 8 Practice Paper
Titration and concentration
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Original practice material written for the MOE GCSE Chemistry syllabus. It is not an official MOE or school examination paper. Chapter 8: concentration in g/dm³, the titration practical and concordant titres, mol/dm³ and titration calculations (Chemistry-only, Higher, badged).
| For Examiner’s Use | |
|---|---|
| Section A | / 10 |
| Section B | / 20 |
| Total | / 30 |
Section A: Multiple-choice questions[10 marks]
Choose one answer for each question. Each question is worth 1 mark.
A flask holds 700 cm³ of solution in which 35 g of solid is dissolved. The concentration, in g/dm³, is
The volume 25 cm³ expressed in dm³ is
In a titration, the alkali is measured by
Titres of 21.60, 21.50 and 21.55 cm³ are obtained. The mean is
The rough titration is discarded because
0.04 mol in 200 cm³ has a concentration of [Chemistry only]
NaOH (Mr 40) at 0.25 mol/dm³ equals [Chemistry only]
25.0 cm³ of 0.1 mol/dm³ NaOH contains [Chemistry only]
The conical flask is rinsed with distilled water because water
A salt made by titration (e.g. ammonium chloride) is crystallised from a solution prepared
Section B: Structured questions[20 marks]
Answer all questions in the spaces provided.
A pharmacy makes 2 dm³ of antiseptic solution containing 30 g of dissolved solid.
Work out the concentration of the antiseptic in g/dm³.
Calculate the mass of solid needed for 150 cm³ of the same solution.
State how the concentration changes if the 30 g is made up to 3 dm³ instead.
A class performs titrations of hydrochloric acid against 25.0 cm³ portions of sodium hydroxide solution.
Burette readings
| Run | Final / cm³ | Initial / cm³ | Titre / cm³ |
|---|---|---|---|
| Rough | 24.50 | 0.00 | 24.50 |
| 1 | 48.20 | 24.50 | 23.70 |
| 2 | 23.85 | 0.10 | 23.75 |
| 3 | 47.50 | 23.85 | 23.65 |
Complete the titre column and identify the concordant runs.
Calculate the mean titre.
State the uncertainty of one burette reading and explain why the mean is trusted more than a single titre.
A student titrates 25.0 cm³ of potassium hydroxide solution with 0.20 mol/dm³ nitric acid. The mean titre is 18.0 cm³. (KOH + HNO₃ → KNO₃ + H₂O. K 39, O 16, H 1, N 14.) [Chemistry only]
Calculate the moles of nitric acid run in.
Deduce the moles of KOH in the flask and its concentration in mol/dm³.
Express the KOH concentration in g/dm³ (Mr 56).
State why the student would not use this titration mixture to make potassium nitrate crystals directly.
— End of paper —