GCSE (9–1) · GCSE Chemistry (Foundation and Higher)
Chapter 6 Practice Paper
The mole and reacting masses
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Original practice material written for the MOE GCSE Chemistry syllabus. It is not an official MOE or school examination paper. Chapter 6: the mole and Avogadro constant, mol = mass ÷ Mr, equations as mole recipes, reacting masses, limiting reactants, molar gas volume (Chemistry-only, Higher).
| For Examiner’s Use | |
|---|---|
| Section A | / 10 |
| Section B | / 20 |
| Total | / 30 |
Section A: Multiple-choice questions[10 marks]
Choose one answer for each question. Each question is worth 1 mark.
The Avogadro constant is the number of particles in
The mass of 0.2 mol of calcium carbonate, CaCO₃ (Ca 40, C 12, O 16), is
How many moles are in 3.2 g of sulfur dioxide, SO₂ (S 32, O 16)?
In 3Fe + 2O₂ → Fe₃O₄, the moles of iron needed to make 4 mol of Fe₃O₄ are
A reaction vessel holds 1 mol of N₂ and 1 mol of H₂ (N₂ + 3H₂ → 2NH₃). The limiting reactant is
At RTP, 0.1 mol of any gas occupies
Which mass of MgO (Mr 40) forms from 3.6 g of Mg with excess oxygen (2Mg + O₂ → 2MgO; Mg 24)?
The number of atoms in 0.5 mol of helium is
2NaHCO₃ → Na₂CO₃ + H₂O + CO₂. From 0.4 mol of NaHCO₃, the moles of Na₂CO₃ formed are
CuO + H₂ → Cu + H₂O. Reducing 8.0 g of CuO (Cu 64, O 16) gives what mass of copper?
Section B: Structured questions[20 marks]
Answer all questions in the spaces provided.
A technician prepares a solution by dissolving 0.15 mol of copper sulfate (CuSO₄, Cu 64, S 32, O 16) in water.
Calculate the Mr of CuSO₄.
Calculate the mass dissolved.
Calculate the number of formula units in the beaker (to 3 significant figures).
The technician actually needs 0.30 mol. State the mass that should have been weighed.
State why doubling the moles doubles the mass.
Aluminium reacts with chlorine: 2Al + 3Cl₂ → 2AlCl₃ (Al 27, Cl 35.5).
A student burns 5.4 g of aluminium in excess chlorine. Calculate the mass of AlCl₃ formed (Mr 133.5).
Calculate the volume of chlorine used up at RTP.
A second student has only 7.1 g of chlorine (0.1 mol) but plenty of aluminium. Calculate the mass of AlCl₃ they can make.
Limestone (pure calcium carbonate) is roasted in a kiln: CaCO₃ → CaO + CO₂ (Ca 40, C 12, O 16). A charge of 250 g of limestone is heated strongly.
Kiln data
| Quantity | Value |
|---|---|
| Limestone charged | 250 g |
| Molar volume at RTP | 24 dm³ |
Calculate the moles of CaCO₃ charged.
Calculate the mass of CaO expected.
Calculate the volume of CO₂ released at RTP if the reaction goes to completion.
After firing, the solid residue actually weighs 154 g. Explain what this shows and calculate the percentage of limestone that decomposed.
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