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Chapter 10 Practice Paper: Statistical Data Handling — mark scheme

QuizQuipPractice Series
QQ/S1MATH/CH10

Secondary 1 · Lower Secondary Mathematics (G2 / G3)

Mark scheme

Statistical Data Handling

Chapter 10 Practice Paper · Maximum mark: 30

Notes for markers

  • Award one mark for each point marked [1], up to the marks shown for the part.
  • Accept answers worded differently that show the same understanding.
  • Units are required where the answer line shows one. ecf: allow an error carried forward.

Section A: Multiple-choice questions[10 marks]

QuestionAnswer
1CThe cycle starts by settling the question; only then is data gathered to answer it.1
2AAdd the two categories: 12 + 8 = 20 pupils.1
3B4 × 3 = 12, and the half symbol adds ½ × 3 = 1.5, giving 13.5 hours.1
4D126/360 = 7/20 of the club, and 7/20 × 40 = 14 members.1
5CA changing quantity measured over time is drawn as a line graph.1
6AOne class ends exactly where the next begins, so the bars touch.1
7DAdd the classes below 3 kg: 14 + 22 = 36 parcels.1
8B90° is a quarter of 360°, so 15 pupils are a quarter of the group: 15 × 4 = 60.1
9BA scale that skips zero makes bar heights exaggerate differences, so read the scale before believing the picture.1
10CThe difference is 4 − 1 = 3 symbols, and 3 × 5 = 15 books.1

Section B: Structured questions[20 marks]

QuestionAnswer and marking pointsMarks
1(a)

Sport, chosen by 18 pupils.

  • Sport with 18 [1]
1
1(b)

12/40 = 3/10 [1]

1
1(c)

Angle = 18/40 × 360° = 162°.

  • Uses 18/40 × 360° [1]
  • 162° [1]
2
1(d)

The activities are separate categories with no order or time scale, so joining them with a line would invent a trend.

  • Categories are not a scale or time order [1]
1
Total for Question 15
2(a)

150/360 = 5/12 [1]

1
2(b)

Members = 5/12 × 60 = 25.

  • Uses 5/12 of 60 [1]
  • 25 members [1]
2
2(c)

Angle = 9/60 × 360° = 54°.

  • Uses 9/60 × 360° [1]
  • 54° [1]
2
Total for Question 25
3(a)

82 − 58 = 24 °C [1]

1
3(b)

Between 0 and 5 minutes (a fall of 14 °C, the steepest drop).

  • 0 to 5 minutes [1]
1
3(c)

Rate = 14 °C ÷ 5 min = 2.8 °C per minute.

  • Divides the 14 °C fall by 5 minutes [1]
  • 2.8 °C per minute [1]
2
3(d)

About 56 °C (accept 55–57 °C): 12 minutes lies between the readings of 58 °C at 10 minutes and 51 °C at 15 minutes.

  • Value between 51 and 58 with a reason [1]
1
Total for Question 35
4(a)

12 + 8 = 20 cats [1]

1
4(b)

The 3 kg up to 4 kg class, with 14 cats.

  • 3 ≤ m < 4 [1]
1
4(c)

The data is grouped, so the heaviest cat is only known to lie somewhere between 5 kg and 6 kg.

  • Grouping hides the individual value [1]
1
4(d)

Angle = 14/40 × 360° = 126°.

  • Uses 14/40 × 360° [1]
  • 126° [1]
2
Total for Question 45

— End of mark scheme —